It is known that f (x) is an odd function whose domain is r, and f (1) = 2, f (0) x f (1) =?

It is known that f (x) is an odd function whose domain is r,
Then f (0) = 0, f (1) = - f (- 1)
∵f(-1)=2,
∴f(1)=-f(-1)=-2
Then f (0) x f (1) = 0-2 = - 2

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