21 + 22 + 23 + 24 +. + 2N-1 total n-1 term summation formula

Let x = 2 ^ 1 + 2 ^ 2 + 2 ^ 3 + 2 ^ 4 +... + 2 ^ (n-1) (1) 2x = 2 ^ 2 + 2 ^ 3 + 2 ^ 4 +... + 2 ^ (n-1) + 2 ^ n (2) (2) - (1) x = 2 ^ n - 2

RELATED INFORMATIONS

1. The {an} is an equal ratio sequence, the sum of the first n terms is Sn, and Sn = 2 to the nth power + a (n ∈ n} to find the value of a and the common term of {α n} The {an} is an equal ratio sequence, the sum of the first n terms is Sn, and Sn = the nth power of 2 + a (n ∈ n ＊) The general formula of a value and {α n} If BN = (2n-1) an, find the first n terms and TN of the sequence {BN} Urgent,
2. 1) It is proved that {lgan} is equal difference 2) {BN} is headed by B1, tolerance is D, and 2 ` B (B power of 2) is equal difference 2 2) Certificate ratio!
3. An * an + 1 = (1 / 2) n power, BN = A2N, prove that {BN} is an equal ratio sequence A1=1
4. What is the law of the power of a number
5. Let's relax and play a number game a2013= The first step is to take a natural number N1 = 4 and calculate the square of N1 plus one = A1 The second part calculates the sum of the numbers of A1 to get N2, and calculates the square of N2 plus one to get A2 The third step is to calculate the sum of the numbers of A2 to get N3, and calculate the square of N3 plus one to get A3 . By analogy, a2013 =?
6. Let's relax and play a number game Step 1: take a natural number N1 = 5 [N1's 1 is the small one in the lower right corner, because it's too troublesome to play, so it's not so clear. Please forgive me.], calculate N1 & # 178; + 1 to get A1; Step 2: calculate the sum of all the numbers of A1 to get N2, calculate N2 & # 178; + 1 to get A2; Step 3: calculate the sum of the numbers of A2 to get N3, and then calculate N3 & # 178; + 1 to get A3 If you list them in turn, you will see 2008=________ .
7. Let's relax and do a math game: Step 1: take a natural number N1 = 5, calculate N12 + 1 to get A1; step 2: calculate the numbers of A1 N 2 is obtained by the sum of N 22 + 1, and a 2 is obtained by calculating n 22 + 1; Step 3: calculate the sum of the numbers of A2 to get N3, and calculate N32 + 1 to get A3; … And so on, then a2011=
8. Let's relax and play a math game The first part: take a natural number N1 = 5, calculate N1 & # 178; + 1 to get A1; Part two: calculate the sum of all the numbers of A1 to get N2, calculate N2 & # 178; + 1 to get A2; Part 3: calculate the sum of the numbers of A2 to get N3, and then calculate N3 & # 178; + 1 to get A3; …… By analogy, a2013 = ▁▁▁▁▁▁▁▁▁▁
9. The X + 1 power of 3 and the X + 1 power of 2 are equal to the 2x-3 power of 6,
10. X + 1 power of solving equation 3 * x + 1 power of 2 = 2x-3 x = several times of 6
11. What is the summation formula of 1 to the power of x plus 2 to the power of X of N?
12. Given that 0 ≤ A-B ≤ 1, 1 ≤ a + B ≤ 4, then when a-2b reaches the maximum, 8A + 2002b is equal to 0______ ．
13. Find the maximum value g (a) of the function y = - cosx ^ 2 + acosx + 5 / 8a-1 / 2 (x is greater than or equal to 0, less than or equal to half)
14. If a equals 5, find 8A plus 12
15. When a = 1, 8A + 6 14
16. When a is more or less, the value of 13-8a is equal to 1 It's an inequality
17. The second power of a + the second power of B - the minimum of 8a-6b + 33
18. Let a and B satisfy a 2-8a + 6 = 0 and 6B 2-8b + 1 = 0, and find the value of AB + 1ab
19. Given 2a-6b + 8 = 36, find the value of 8a-24b-5
20. 1/(1*2)+1/(2*3)+1/(3*4)+... ...+1/(99*100)