When a solid iron ball is put into water, the buoyancy is F1. When it is put into mercury, the buoyancy is F2. The known iron density is 7.8, and the mercury density is 13.6, then calculate F1: F2—— thirty-nine But I figured it out to be 1:13.6

The density of iron is higher than that of water, iron sinks into water, F1 = density of water * VG
Iron density is smaller than mercury, iron floats, F2 = m, iron * g = iron density * VG
F1 / F2 = density of water / density of iron = 5 / 39

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