Put a solid metal ball into the mercury, and the metal ball floats on the mercury surface. At this time, the buoyancy of the metal ball is 19.6n. If the metal ball is immersed in water, the indication of the spring dynamometer is 17.5n, and the known metal density is 8 times 10 to the third power kg / cm3 The gravity of a metal ball 2 mass and volume of metal ball Buoyancy of metal ball in water I only have five hours, I'm almost crying

1. Because of floating, f floating = g matter = 19.6n2. M = g / g = 19.6n/9.8n/kg = 2kg, v = m / P = 2kg / 8 × 10-179; kg / m3 = 2.5 × 10-4m-179; 3. Immersion in water, so: V row = V matter, f floating = PGV row = 1.0 × 10-179; kg / m-179; × 9.8n/kg × 2.5 × 10-4m-179; = 2

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