When the apple with a mass of 0.27kg floats in the water, about 110% of the volume is above the water surface, as shown in the figure. Please answer (g = 10N / kg): (1) the buoyancy of the apple? (2) The density of apples?

(1) The results show that the buoyancy of apple is as follows: f-floating = g = mg = 0.27kg × 10N / kg = 2.7N; (2) the volume of Apple immersed in water (volume of boiled water): v-row = f-floating, ρ water g = 2.7n1 × 103kg / m3 × 10N / kg = 2.7 × 10-4m3, ∵ Apple has 110 volume above the water surface, v-row = 910v, ∵ Apple volume: v = 109v-row = 109 × 2.7 × 10-4m3 = 3 × 10-4m3, apple density: ρ = MV = 0.27kg3.0 × 10 − 4m3 = 0.9 Answer: (1) the buoyancy of apple is 2.7N; (2) the density of apple is 0.9 × 103kg / m3

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