As shown in the figure, in diamond ABCD, e and F are the points on BC and CD respectively, ∠ B = ∠ EAF = 60 ° and ∠ BAE = 20 ° to find the degree of ∠ CEF

As shown in the figure, in diamond ABCD, e and F are the points on BC and CD respectively, ∠ B = ∠ EAF = 60 ° and ∠ BAE = 20 ° to find the degree of ∠ CEF

Connecting AC, as shown in the figure, connecting AC, connecting AC, connecting AC, as shown in the figure, connecting AC, in the diamond ABCD, in the diamond ABCD, ab = BC, ab = BC, \ \\\\\? In the diamond ABCD, ab = BC, \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\sidethree According to the properties of the external angle of the triangle, ∠ AEF + ∠ CEF = ∠ B + ∠ BAE,  60 ° + ∠ CEF = 60 ° + 20 °, the solution ∠ CEF = 20 ° is obtained