For the formula 2 (3 + 1) (32 + 1) (34 + 1) (38 + 1) (316 + 1) (332 + 1) + 1, do you know the number of digits it calculates

2 (3 + 1) (3 ^ 2 + 1) (3 ^ 4 + 1) (3 ^ 8 + 1) (3 ^ 16 + 1) (3 ^ 32 + 1) + 1 = (3-1) (3 + 1) (3 ^ 2 + 1) (3 ^ 4 + 1) (3 ^ 8 + 1) (3 ^ 16 + 1) (3 ^ 32 + 1) + 1 = (2 ^ 2-1) (3 ^ 2 + 1) (3 ^ 4 + 1) (3 ^ 8 + 1) (3 ^ 16 + 1) (3 ^ 32 + 1) + 1 =. = (3 ^ 32-1) (3 ^ 32 + 1) + 1 = 3 ^ 64, because LG (3 ^ 64) = 64 * LG (3

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