Given the parallelepiped abcd-a'b'c'd '. Find the vector AC' + the vector d'b-the vector DC

The following vectors AB, ad. and so on are abbreviated as ab, AD.AC '= AB + AD + aa'd'b = d'd + d'a' + d'c'parallelepiped abcd-a'b'c'd'ab = d'c ', ad = - d'a', AA '= - d'd, ab = DCAC' + d'b-dc = AB + AD + AA '+ d'd + d'a' + d'c '- DC = AB + AD + AA' - AD + ab-dc = 2ab-dc

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