In the RT triangle ABC, if ∠ C = 90 ° AB = 13 and the radius of the inscribed circle is 2, the perimeter of the triangle ABC is 0 Such as the title

Let two right angle sides be, a, B
Then (A-2) + (b-2) = 13
And a ^ 2 + B ^ 2 = 13 ^ 2
The results of solving equations
a=5,b=12
So the perimeter is 30

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