As shown in the figure, Mn and PQ are parallel smooth metal guide rails with a spacing of L. they are placed in a uniform magnetic field with a magnetic induction intensity of B and a direction perpendicular to the plane of the guide rail. M and P indirectly have a resistance of R. a metal wire AB with good contact with the guide rail and an effective resistance of R2 is placed vertically on the guide rail and moves to the right at a uniform speed V under the action of horizontal external force F, regardless of the resistance of the guide rail , then () A. The direction of current through resistance R is p → R → MB. The voltage between two points is blvc. The potential at a end is higher than that at B end. The work done by external force F is equal to Joule heat generated in the circuit

As shown in the figure, Mn and PQ are parallel smooth metal guide rails with a spacing of L. they are placed in a uniform magnetic field with a magnetic induction intensity of B and a direction perpendicular to the plane of the guide rail. M and P indirectly have a resistance of R. a metal wire AB with good contact with the guide rail and an effective resistance of R2 is placed vertically on the guide rail and moves to the right at a uniform speed V under the action of horizontal external force F, regardless of the resistance of the guide rail , then () A. The direction of current through resistance R is p → R → MB. The voltage between two points is blvc. The potential at a end is higher than that at B end. The work done by external force F is equal to Joule heat generated in the circuit

A. According to the right-hand rule, the direction of induced current in AB is B → a, then m → R → P. so a is wrong; the voltage between B and ab is the terminal voltage. According to Ohm's law of closed circuit, the voltage between AB is u = RR + 12re = 23blv. So B is wrong. C and metal wire AB are equivalent to the power source, and a terminal is equivalent to the positive pole of the power source, so C is correct In uniform linear motion, according to the conservation of energy, the work done by the external force F is equal to the Joule heat generated in the circuit. Therefore, D is correct. Therefore, CD is selected