Put the cube iron block weighing 77.42n on the tabletop with an area of 1m2. What is the pressure of the iron block on the tabletop? The density of iron is the third power of P = 7.9 * 10

Put the cube iron block weighing 77.42n on the tabletop with an area of 1m2. What is the pressure of the iron block on the tabletop? The density of iron is the third power of P = 7.9 * 10

From g = mg, what is the mass equal to
Then the volume of the iron block is calculated from the mass = density × volume
The volume is equal to the cube of the side length. After calculating the side length, the bottom area is equal to the square of the side length, and the bottom area is calculated
P = f / s, f = g, so that's the pressure
(because I'm really lazy, I didn't count. I believe you're smart enough to understand.)