A cube iron block weighing 77.42n is placed in the center of a 1m cubic horizontal tabletop. What is the pressure of the iron block on the tabletop?

A cube iron block weighing 77.42n is placed in the center of a 1m cubic horizontal tabletop. What is the pressure of the iron block on the tabletop?

V Fe = g / GP Fe = 77.42n △ 9.8n/kg △ 7900kg / M & sup3; = 0.001M & sup3;
So S-Fe = 0.01 M2 < 1m & sup3;
P=F/S=77.42N/0.01㎡=7742Pa