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Given the line segments a, B, m (a > b > m), find △ ABC, so that ab = a, AC = no, the middle line ad on the side of BC = M. how to draw, and what is the reason? Given the line segments a, B, m (a > b > m), find △ ABC so that ab = a, AC = B, ad = m on the edge of BC. What is the reason for how to draw? (correction)
Let a, B, 2m be sides, make triangle ace and make AC = B, CE = a, AE = 2m make ray AQ make AQ ‖ CE move CE to AQ and cross AQ to BAE, BC cross D connect a, B, C, then abce is parallelogram, D is the midpoint of AE, AE = 2mad = m and AC = B, ab = a
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