A problem of number axis and linear equation Find out the linear equation of triangle area 12 which is the intersection of two lines x-2y + 8 = 0 and 3x + 2Y = 0 and cut with the negative half axis of X axis and positive half axis of Y axis

A problem of number axis and linear equation Find out the linear equation of triangle area 12 which is the intersection of two lines x-2y + 8 = 0 and 3x + 2Y = 0 and cut with the negative half axis of X axis and positive half axis of Y axis

Let the linear equation be: Y-3 = K (x + 2) (k > 0) when x = 0, y = 2K + 3 when y = 0, x = - (2 + 3 / k) s = 1 / 2 * | 2K + 3 * | 2 + 3 / K | = 12, the solution is: k = 3 / 2, so the linear equation is: Y-3 = 3 / 2 (x + 2), that is: 3x-2y + 12 = 0