If an is an equal ratio sequence composed of positive numbers and A4 * A5 = 8, then log2a1 + log2a2 +... + log2a8=

log(2)[a1]＋log(2)[a2]＋… ＋log(2)[a8]
=log(2)[(a1)×(a2)×(a3)×… ×(a8)]
Because a1a8 = a2a7 = a3a6 = a4a5 = 8
Then the original formula = log (2) [8 × 8 × 8 × 8] = 12

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