Using the method of dislocation subtraction to find the first n terms and the higher one sequence Given the square of. An = 4N, find the sum of the first n terms of. BN = 1 / 2-1 of an ^ 2-1

BN = an ^ 2-1 / 1 = 1 / [(an + 1) (an-1)] = 1 / 2 (an-1) - 1 / 2 (an + 1) the sum of the preceding n terms is: 1 / 2 (an + 1) - 1 / 2 (an-1) + 1 / 2 (An-2) + 1 / 2 (an-1) - 1 / 2 (an-3) +. + 1 / 2a3-1 / 2A1 + 1 / 2a2-1 / 2a0 = 1 / 2 (an + 1) + 1 / 2an-1 / 2a0 = 1 / [2 * 4 ^ (n + 1)] + 1 / (2 * 4N ^ 2) - 1 / 2 *

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