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When an = (1 / 2n-1) * (3 / 4) ^ n, how much is Sn equal to
For a new sequence obtained by multiplying the arithmetic sequence and the proportional sequence, we usually use the dislocation subtraction method to find the first n terms and Sn of the sequence. First, we list the expansion of Sn, and then multiply both sides by the common ratio (q) of the arithmetic sequence. After subtraction, we can get the expression of (1-Q) Sn, and then we can solve it, This is the product of the arithmetic sequence and the proportional sequence
RELATED INFORMATIONS
- 1. An = nx2n square for Sn dislocation subtraction
- 2. It is known that {an} satisfies an = (3N + 1) 2 ^ (n + 1), and Sn is obtained by subtraction of dislocation
- 3. An = n times 3 ^ n, find Sn (dislocation subtraction, detailed process)
- 4. 3 sum Sn = 1 (1 / 3) + 3 (1 / 3) ^ 2 + 5 (1 / 3) ^ 3 + +(2n-1) (1 / 3) ^ n (I used the method of dislocation subtraction for a long time, but I can't solve it later
- 5. Sum: x + 3x ^ 2 + 5x ^ 3 +... + (2n-1) x ^ n
- 6. When x is not equal to 1,0, 1 + 3x + 5x ^ 2 + +What is (2n-1) x ^ (n-1) equal to
- 7. Given the function f (x) = 3x / x + 3 (x is not equal to negative 3, X belongs to R), the sequence {a small n} satisfies a small n = f (a small n minus 1) (n is greater than or equal to 2, n belongs to n) and A1 is unequal Given the function f (x) = 3x / x + 3 (x is not equal to negative 3, X belongs to R), the sequence {a small n} satisfies a small n = f (a small n minus 1) (n is greater than or equal to 2, n belongs to n) and A1 is not equal to 0 (1). Prove: the sequence {1 / a small n} is an arithmetic sequence (2). If A1 = 1 / 4, find the value of a small 50
- 8. Sum by dislocation subtraction: sum: SN = 1 + 3x + 5x2 + 7X3 + +（2n-1）xn-1．
- 9. Sum: SN = 1 + 3x + 5x + 7x + +﹝2n-1﹞x^n-1
- 10. Given the first n terms of the sequence {an} and Sn = an − 1 (a ≠ 0), then the sequence {an} () A. It must be an arithmetic sequence B. it must be an arithmetic sequence C. It must be an arithmetic sequence or an arithmetic sequence D. It is neither an arithmetic sequence nor an arithmetic sequence
- 11. The solution is: SN = 1 × 2 + 3 × 4 + 5 × 8 +. + (2n-1) 2 * n (this represents the nth power of 2)
- 12. What is the meaning of "equal difference multiplied by equal ratio" in dislocation subtraction method
- 13. How to calculate the dislocation subtraction method in the proportional sequence? I don't quite understand this algebra
- 14. Examples of dislocation subtraction in sequence an=4n-2 bn=2/[4^(n-1)] cn=an/bn Finding the first n terms and TN of CN of sequence
- 15. Using the method of dislocation subtraction to find the first n terms and the higher one sequence Given the square of. An = 4N, find the sum of the first n terms of. BN = 1 / 2-1 of an ^ 2-1
- 16. It is urgent to find the sum of sequence dislocation subtraction The calculation problem is urgent
- 17. High school mathematics what kind of sequence can use superposition to find Sn, what kind of sequence can use dislocation subtraction to find Sn, it's better to be more detailed and list all the possibilities
- 18. High school mathematics sequence dislocation want to reduce
- 19. Easy to understand, I have a poor foundation, too abstruse to understand ~
- 20. Senior three a round of sequence sequence sum dislocation subtraction homework master into ah It is known that the tolerance D of the arithmetic sequence an is greater than 0, and A2 and A5 are two of the equations x ^ 2-12x + 27 = 0. The sum of the first n terms of the sequence BN is TN, and TN = 1-1 / 2bn (1) Finding {an} {BN} will find that an = 2N-1, BN = 2 / 3 * [(1 / 3) of the N-1 power] (2) Note CN = anbn, find the first n terms of {CN} and Sn Is to seek the second question of dislocation subtraction!