It is known that SN is the sum of the first n terms of the sequence an, and Sn = 2-2an 1. Prove that the sequence an is an equal ratio sequence 2. Find the general term formula of the sequence an 3. Find the first n terms and wn of the sequence {ANSN} We need a specific process

An = SN-S (n-1) = - 2An + 2A (n-1) 3an = 2A (n-1) an / a (n-1) = 2 / 3 equal ratio sequence, common ratio = 2 / 3s1 = 2-2a1 = A1, A1 = 2 / 3an = A1 * q ^ (n-1) = (2 / 3) ^ nansn = (2 / 3) ^ n * (2-2 * (2 / 3) ^ n) = 2 (2 / 3) ^ n-2 (2 / 3) ^ (2n) = (4 / 3) (2 / 3) ^ (n-1) - (8 / 9) (4 / 9) ^ (n-1) wn = [(4 / 3) ((2 / 3) ^ (2 / 3) ^ (2 / 3) ^ (2) ^ (2 / 3) ^ (2) ^ (2 / 3) ^ (2) ^ (2 / 3) ^ (2) ^ (2 / 3) ^ (2) ^

RELATED INFORMATIONS

1. If M > 1, am-1 + am + 1-am2 = 0, s2m-1 = 38, then M is equal to () A. 38B. 20C. 10D. 9
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10. If A1 = 1, an = - 152 and the sum of the first n terms is Sn = - 341, then the common ratio q =? Number of terms =?
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14. Let the first n terms of sequence {an} and Sn = 2an-2 ^ n (1) prove that {a (n + 1) - 2An} is the general term of finding {an} from the equal ratio sequence (2) The second question doesn't matter. Try to do it
15. Let the first n terms of sequence {an} and Sn = 2an-2n (1) prove that sequence {an + 1-2an} is equal difference sequence (2) prove that sequence {an + 2} is equal ratio sequence (3) The general term formula of {an}
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20. Given that the sum of the first n terms of the sequence {an} is Sn, and Sn = n-5an-85, n ∈ n *, it is proved that {an-1} is an equal ratio sequence