(6 out of 7 + 2 out of 5) × 7 × 5, calculated by a simple method

RELATED INFORMATIONS

• 1. (1.25 + 2.5) × 16 = 1.25 × 3.7 × 0.8 = 3.4 × 9 + 3.4 = 9.24 × 9 + 3.4 = simple calculation
• 2. 5×[6.8-（1.6+3.6÷0.9）]÷84．
• 3. How about 3.24 × 0.16 + 0.0324 × 84?
• 4. To simplify the following ratio: 341:209 3 / 20:7 / 45 11 / 12:5 / 24 6 and 1 / 2:2 / 5 56:84 465:375 14 and 4 / 5:3 and 3 / 7
• 5. (3 + 1) (3 ＾ 2 + 1) (3 ＾ 4 + 1) (3 ＾ 8 + 1) (3 ＾ 16 + 1) evaluation
• 6. Evaluation: 0.125 ^ - 1 / 3 - (- 1 / 2) ^ - 2 + 16 ^ 0
• 7. The solution proportion: (1) x: 3 / 8 = 2 / 3: 4 (2) x: 6 = 2 / 7 (3) x: 0.3 = 0.4:0.8 (4) 1.75 = 6 / 6 x
• 8. (0.0081) ^ - 1 / 4 - [3 * (7 / 8) ^ 0] ^ - 1 * [81 ^ - 0.25 + (27 / 8) ^ - 1 / 3] ^ - 1 / 2-10 * 0.027 ^ 1 / 3 important process
• 9. (0.0081)^-1/4-[3*(7/8)^0]^-1*[81^-0.25+(27/8)^-1/3]^-1/2-10*0.027^1/3=?
• 10. 81^1/2-(1/8)^-1+3^0=?
• 11. The ratio is 3.75:2.5 2 / 3:1 / 4
• 12. To calculate the ratio, the formula is 0.52:1.3, 2:12:7, and the simple ratio is 1.25:2.5, 4:0.125
• 13. 5 / 8 ton: 750 kg ratio 1.2:5 / 4 ratio 2.5 meter: 50 cm ratio
• 14. The ratio: 1 / 4 ton: 375 kg; 2 / 3: 45; 1 / 2: 0.75; 3 / 5 ton: 400 kg
• 15. The number of large cubes is 1 23 4 5 6 7 8, the number of small cubes is 8 16 24 32 40 48 56 64, can't four small cubes spell the big one?
• 16. The data of time and temperature in an experiment are recorded in the following table: time 0,5,10,15,20,25,30, temperature 8,16,24,32,40,48,56 (1) If the temperature change is uniform, calculate the temperature when the time is Tmin. (2) calculate the temperature when the time is 16min
• 17. 1.32:12 2.3.5:1.25 3.0.05:3 4.1:0.05 6.2.45:1.4 [ratio]
• 18. Simplify the following ratios and calculate the ratio: (with process) 2 / 5 ∶ 1 / 4 1 / 20 ∶ 1 / 4 0.25 ∶ 1 48 / 32
• 19. The ratio is 0.36:1.36:0.32 2:25 120.25:6 5:8
• 20. Simplify the following ratio: 7:4:3 20:6:5 1:0.75 120:32 36:5:9 10 2:3:9:4:8:5:4 1.25:0.25