Δ ABC is an equilateral triangle, point E is the point on the extension line of BC, the vertical bisector of be is called AC at point D, and the perpendicular foot is m, CE = CD

Δ ABC is an equilateral triangle, point E is the point on the extension line of BC, the vertical bisector of be is called AC at point D, and the perpendicular foot is m, CE = CD

prove:
∵ △ ABC is an equilateral triangle
∴∠ACB=60°
∵CD=CE
∴∠E=∠CDE=30°
DM vertical bisection be
∴DB=DE
∴∠DBE=∠E=30°
∵∠ACB=60°
∴∠BDE=90°
∵BC=BA
∴AD=CD