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證明: ∵△ABC是等邊三角形 ∴∠ACB=60° ∵CD=CE ∴∠E=∠CDE=30° ∵DM垂直平分BE ∴DB=DE ∴∠DBE=∠E=30° ∵∠ACB=60° ∴∠BDE=90° ∵BC=BA ∴AD=CD
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