In △ ABC, a = 32 °, B = 81.8 ° and a = 42.9cm 2 in △ ABC, a = 20cm, B = 28cm, a = 40 ° to solve triangle 3 in △ ABC, a = 2 √ 3, C = √ 6 + √ 2, B = 60 ° to find B and a 4 in △ ABC, a = 134.6cm, B = 87.8cm, C = 161.7cm, solve triangle 5 in △ ABC, if a & sup2; = B & sup2; + BC + C & sup2;, then a =? 6 in △ ABC, if sinA:sinB If: sinc = 7:8:13, then C =? 7 in △ ABC, ab = √ 6 - √ 2, C = 30 °, then the maximum value of AC + BC is? 8 in △ ABC, if Asina + bsinb = csinc, what is the shape of △ ABC? 9 in △ ABC, prove a / B-B / a = C (CoSb / b-cosa / a)

In △ ABC, a = 32 °, B = 81.8 ° and a = 42.9cm 2 in △ ABC, a = 20cm, B = 28cm, a = 40 ° to solve triangle 3 in △ ABC, a = 2 √ 3, C = √ 6 + √ 2, B = 60 ° to find B and a 4 in △ ABC, a = 134.6cm, B = 87.8cm, C = 161.7cm, solve triangle 5 in △ ABC, if a & sup2; = B & sup2; + BC + C & sup2;, then a =? 6 in △ ABC, if sinA:sinB If: sinc = 7:8:13, then C =? 7 in △ ABC, ab = √ 6 - √ 2, C = 30 °, then the maximum value of AC + BC is? 8 in △ ABC, if Asina + bsinb = csinc, what is the shape of △ ABC? 9 in △ ABC, prove a / B-B / a = C (CoSb / b-cosa / a)

The angle of the first sine theorem can only be calculated by the formula of the second sine theorem, the third B & sup2; = A & sup2; + C & sup2; + 2accosb, and then the angle can be calculated by the sine theorem, the fourth can only be calculated by the cosine theorem, the fifth can be carried by the formula of the cosine theorem, and the sixth can get a: B: C = 7