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Veda's law + two roots + solving quadratic equation with one variable Using Veda's law, if two equations are known, write out the quadratic equation of one variable X1=8 X2=3;
X1+X2=11
X1*X2=24
Let the quadratic equation be x ^ 2 + PX + q = 0;
∵ according to Weida's theorem, we can see that:
X1+X2=-P;
X1*X2=Q;
∴-P=11;
Q=24;
P = - 11;
Q=24;
Therefore, the quadratic equation of one variable is as follows:
X^2-11X+24=0.
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