The problem of Veda's law If Aerfa and Beita are two of the equations x ^ 2-2x-2001 = 0, find Aerfa ^ 2 + 3aerfa + Beita If α β is two of the equation x ^ 2-2x-2001 = 0, find the value of α ^ 2 + 3 α + β

First of all, I suspect you have made a mistake. It should be x ^ 2 + 2x-2001 = 0
If so, α ^ 2 + 2, α - 2001 = 0, α + β = - 2
α^2+3α+β=α^2+2α-2001+α + β+2001=2001-2=1999

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