Quadratic term theorem problem! Urgent! It is proved that: (2 ^ 6n-3) + (3 ^ 2n-1) can be divisible by 11 sorry, The title should be 2 ^ (6n-3) + 3 ^ (2n-1)

2^(6n-3)+3^(2n-1）=8^(2n-1)+3^(2n-1)=(8+3)*(8^(2n-2) - 8^(2n-3)*3^1 + …… + 3^(2n-1))=11*(8^(2n-2) - 8^(2n-3)*3^1 + …… +3 ^ (2n-1)) = > (2 ^ 6n-3) + (3 ^ 2n-1) can be divided by 11

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