It is known that a multiplied by 6 / 7 equals B multiplied by 6 / 5 equals C, where ABC is a natural number and cannot be zero

It is known that a multiplied by 6 / 7 equals B multiplied by 6 / 5 equals C, where ABC is a natural number and cannot be zero

a*6/7=b*6/5=c
Let the original formula be 1, then a = 7 / 6, B = 5 / 6, C = 1
∴b<c<a