ABC is a non-zero natural number, and a multiplied by 5 / 4 equals B multiplied by 3 / 4 equals C multiplied by 3 / 2, then the three numbers of ABC are arranged as ()

a*5/4=b*3/4=c*3/2
Multiply by 4
5a=3b=6c
Suppose C = 5, then
b=10
a=6
So b > a > C

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