In triangle ABC, angle a = 3, angle B, angle a-angle C = 30 degrees, then angle a =? Angle B =? Angle c =?

In triangle ABC, angle a = 3, angle B, angle a-angle C = 30 degrees, then angle a =? Angle B =? Angle c =?

Let a = X
Then ∠ B = x / 3, ∠ C = X-30
∠A+∠B+∠C=180°
x+x/3+x-30=180°
∠A=x=90°
∠B=x/3=30°
∠C=x-30=60°