It is known that a ＞ B ＞ C, and verified that 1a − B + 1b − C ≥ 4A − C

It is proved that: ∵ a − Ca − B + a − CB − C = a − B + B − Ca − B + a − B + B − CB − C = 2 + B − Ca − B + a − BB − C ≥ 2 + 2B − Ca − B × a − BB − C = 4, (a ＞ B ＞ C) ∵ a − Ca − B + a − CB − C ≥ 4 ∵ 1a − B + 1b − C ≥ 4A − C

RELATED INFORMATIONS

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