Let a = {X-Y, x + y, XY} B = {X & sup2; + Y & sup2;, - X & sup2; - Y & sup2;, 0} if a = B, find the value of real number x, y Come on, speed up

Let a = {X-Y, x + y, XY} B = {X & sup2; + Y & sup2;, - X & sup2; - Y & sup2;, 0} if a = B, find the value of real number x, y Come on, speed up

1) Xy = 0x = 0A = {- y, y, 0) B = {y ^ 2, - y ^ 2,0} because a = B, y ^ 2 = y = > y = 1, {x = 0 {y = 12) 0 = x-ya = {0, x, x ^ 2} B = {2x ^ 2, - 2x ^ 2,0} from B, we can see that non-zero elements are opposite to each other, so non-zero elements in a are opposite to each other, x = - x ^ 2x = - 1A = {0, - 1,1} B = {0, - 2,2} contradiction! So 0 ≠

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