If the density of sea water is 1.1 × 103kg / m3 and the density of ice is 0.9 × 103kg / m3, what is the volume of the iceberg exposed to the sea?

If the density of sea water is 1.1 × 103kg / m3 and the density of ice is 0.9 × 103kg / m3, what is the volume of the iceberg exposed to the sea?

If ∵ ρ ice ∵ ρ water, ∵ ice should float in water, f float = g ice = ρ ice V ice g and ∵ f float = g row = ρ liquid V row g, ∵ ρ ice V ice g = ρ liquid V row g ∵ V ice = V row + V dew, ∵ V row = (V ice-v dew) ∵ ρ ice V ice g = ρ liquid (V ice-v dew) GV ice − V dew V ice = ρ ice ρ liquid = 0.9 × 103kg / M31 × 103kg / m3 = 911 It's 211.5 percent of the total volume