Now there is 98% ethanol, how to prepare 75% ethanol

Let the solute of 98% ethanol be 0.98x, then the mass of solution is x, the mass of water is 0.02x, and the mass of water is y
0.98x/(0.02x+y)=0.75
0.98x=0.015x+0.75y
0.75y=0.965
y≈1.29
So y: x = 1.29:1
So mix x parts of 98% ethanol and 1.29 parts of pure water

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