Sin1 degree, what formula can you work out

Sin1 degree, what formula can you work out

sin1=y/1
Y is about equal to the arc of 1 degree;
y≈π/180
sin1=0.01745

How to set up the equation [8 x] 3 = 34x

[8x]3=34x
[8]3*[x]3=34x
512*[x]2=34
[x]2=34/512=17/256
So x = plus minus root 17 / 16

Kneel down and ask for the answers of several mathematics problems in Volume 1 of grade 2 of junior high school: 1, (a + b) ² = 9, (a-b) ² = 5, find the values of a & #178; + B & #178; and ab
2. Given A-1 / a = 7, find the value of a & # 178; + 1 / A & # 178
3. If in the product of (X & # 178; + ax-b) (2x & # 178; - 3x + 1), the coefficient of X & # 179; is 5, and the coefficient of X & # 178; is - 6, find a and B
4. If 1 + X + X & # 178; + X & # 179; = 0, find x + X & # 178; + X & # 179; + +The value of X to the power of 2012
Please answer quickly! Urgent need!
There should be a specific process!!!!

1.7 1
two point five one
3.a=4 b= -2/5
four

In the plane rectangular coordinate system, we know that point a (0,2) and point P (x, 0) are the moving points on the x-axis. When x is equal to, the length of line PA is the smallest,
What is the minimum value

In the plane rectangular coordinate system, the point a (0,2) is known,
Point P is a moving point on the x-axis,
When x = (0), the,
The length of line PA is the minimum, and the minimum value is (2)

Let's meet at my home at 9 o'clock

Lion tiger elephant
Let us meet me at my house at

If a straight line passes through a point (5,2) and the intercept on x-axis and y-axis is equal, the equation of the straight line is obtained
I want to know how to do 2x-5y = 0

The intercept is equal on the X and Y axes
Let the linear equation be
x/a+y/a=1
Point substitution
5/a+2/a=1
a=7
So the linear equation is
x/7+y/7=1
x+y-7=0
There is another answer that should consider intercept 0
The solution is 2x-5y = 0
I was careless and sweating

Integral of (sinxcosx) / {(SiNx ^ 4 + (cosx) ^ 4}

It is known that the image of the first-order function Y1 = 3x-2k intersects the image of the inverse scale function y2 = k − 3x, and the ordinate of one of the intersections is 6. (1) find the analytic expressions of the two functions; (2) find the value range of X when Y1 < Y2 by combining with the image

(1) Let the intersection a (m, 6) have 3M − 2K = 6K − 3M = 6 ｛ M = − 43K = − 5 ｛ Y1 = 3x + 10, y2 = − 8x; (2) from the equations 3x + 10 = y − 8x = y, we get 3x2 + 10x + 8 = 0x1 = - 2, X2 = − 43. From the image, we can see that when x ＜ - 2 or − 43 ＜ x ＜ 0, Y1 ＜ Y2

F (x) = - 2x + 8, then f (3x ^ + 4x + 7) = what

Take 3x ^ + 4x + 7 as X in - 2x + 8
f(3x^+4x+7)=-2*（3x^+4x+7）+8
=.

Simple operation of 136 minus 136 multiplied by 5 / 4 minus 136 multiplied by 0.2

It's four fifths
=136 × (4-0.2 out of 1-5)
=136×0
=0