Given that a * 3 / 7 = 12 / 11 * b = 15 / 15 * C, and ABC is not equal to 0, the three numbers of ABC are arranged from small to large Denominator / numerator /: fractional line

The order of the three numbers from small to large is: B C a

It is known that a * 4 / 3 = 12 / 11 * b = 15 / 15 * C and ABC is not equal to 0. The three numbers ABC are arranged in order from large to small
It is known that a * 4 / 3 = 12 / 11 * b = 15 / 15 * C, and ABC is not equal to 0. Arrange the three numbers of ABC from large to small, and explain why

Let a * 4 / 3 = 12 / 11 * b = 15 / 15 * C = 1
be
a=3/4
b=11/12
c=1
c>b>a

In a plan with a scale of 1:200, a rectangular flowerbed is measured to be 4.5cm long and 3cm wide. The actual area of the flowerbed is

Length 4.5x200 = 900cm = 9m
Width 3x200 = 600cm = 6M
The actual area is 9x6 = 54 square meters
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Mathematics problems about the equation of one variable and one degree in Grade Seven
If the equation (M + 1) x square + 2mx = 0 of X is a linear equation of one variable, then M=_______

m=-1

Divide a right angle trapezoid into four parts with the same shape and size

Four right angle trapezoids
The line between the intersection of the center line of the upper bottom and the center line of the height (not the right angle side) and the right angle vertex of the lower bottom

Is the motion of the train translation or rotation
Some people say it's translation, but its wheels don't rotate. / why translation?
If the train is translational, what about a straight-line bicycle?
I am a Junior 1 student, met a problem, students are arguing for the time, ask the teacher also no result
The motion of the train belongs to translation, but it also has wheels. If I ask you whether the train is translation or rotation, how to answer?
Questioner: my rul

It's both translation and rotation. It depends on how you choose the reference object!

Let a, B and C be three points on a circle with radius 1. If AB = 3 ^ (1 / 2), what is the maximum product of vector AB and vector AC

According to the definition: the scalar product of two vectors is equal to the product of the modulus of one vector and the projection of the other vector in the direction of this vector. We know that the projection of vector AC on AB is the largest only when a and C pass through the center of the circle. Draw a graph, and then: becomes the problem of finding BAC

As shown in the figure, in the equilateral triangle ABC, Bo and co divide ∠ ABC, ∠ ACB, OE ‖ AB, of ‖ AC equally, and try to explain be = EF = FC

It is proved that: ∵ ABC is equilateral triangle, ∵ ABC = ∠ ACB = 60 °, ∵ OE ‖ AB, of ‖ AC, ∵ OEF = ∠ ABC = 60 °, ∵ ofe = ∠ ACF = 60 °, ∵ OEF = ∠ ofe, ∵ EOF = 60 °, ∵ OEF is equilateral triangle, ∵ OE = of = EF, ∵ Bo, CO divide ∵ ABC, ∵ ACB, ∵ a equally

Two compulsory problems in senior high school mathematics
1、 The straight line L passes through P (5,5) and intersects with the circle C: X2 (square) + Y2 (square) = 25. The chord length is 4 times the root sign 5 and the equation of L is obtained
2、 Given the endpoint B (1,3) of line AB, the endpoint a moves on the circle C: (x + 1) 2 (square) + Y2 (square) = 4. Find the trajectory of the midpoint m of line AB and its equation. There are two intersections A and D between line L passing through point B and circle C. when OA is perpendicular to OD, find the slope of L
Help answer, please take the process, thank you!!!

1. Let l be y = kx-5k + 5, y ^ 2 = k ^ 2x ^ 2 + (10k-10k ^ 2) x + 25K ^ 2-50k + 25
(1+k^2)x^2+(10k-10k^2)x+25k^2-50k=0
X1+x2=(10k^2-10k)/(1+k^2),x1x2=(25k^2-50k)/(1+k^2)
(X1-x2)^2=(X1+x2)^2-4x1x2=(10k^2-10k)^2/(1+k^2)^2-4(25k^2-50k)/(1+k^2)
=[(10k(k-1))^2-100k(k-2)(1+k^2)]/(1+k^2)^2
(y1-y2)^2=k^2(X1-x2)^2
(X1-x2)^2+(y1-y2)^2=(1+k^2)(X1-x2)^2
=[(10k(k-1))^2-100k(k-2)(1+k^2)]/(1+k^2)
[(10k(k-1))^2-100k(k-2)(1+k^2)]/(1+k^2)=80
The results show that 2K ^ 2-5k + 2 = 0, K1 = 1 / 2, K2 = 2
The line L is x-2y + 5 = 0, or 2x-y-5 = 0
two
(1) Let the coordinates m (x, y) of the midpoint of the line AB and a point on the circle (x0, Y0)
Then x = (x0 + 1) / 2, x0 = 2x-1; y = (Y0 + 3) / 2, Y0 = 2y-3
(2x) ^ 2 + (2y-3) ^ 2 = 4, sorting x ^ 2 + (Y-3 / 2) ^ 2 = 1
(2) To be solved (complex)

Known: as shown in the figure, ab ‖ CD, if ∠ Abe = 130 ° and ∠ CDE = 152 °, then ∠ bed=______ Degree

Make straight line EF ‖ AB, ∵ ab ‖ CD, ∵ EF ‖ CD, ∵ ab ‖ EF, ∵ 1 = 180 ° - ∵ Abe = 180 ° - 130 ° = 50 °; ∵ EF ‖ CD, ∵ 2 = 180 ° - ∵ CDE = 180 ° - 152 ° = 28 °; ∵ bed = ∵ 1 + ∵ 2 = 50 ° + 28 ° = 78 °. So fill in 78

Given that a * 3 / 7 = 12 / 11 * b = 15 / 15 * C, and ABC is not equal to 0, the three numbers of ABC are arranged from small to large Denominator / numerator /: fractional line