Given that a = 1.5 = B multiplied by 85% = C multiplied by 3 / 4 [ABC is not zero], then the three numbers of A.B.C are arranged from small to large

Given that a = 1.5 = B multiplied by 85% = C multiplied by 3 / 4 [ABC is not zero], then the three numbers of A.B.C are arranged from small to large

So B = 1.5/85% is about 1.76, C = 1.5/0.75 = 2
So a is less than B and less than C

Geometric meaning of second derivative of function

The significance is as follows:
(1) The rate at which the slope of the diagonal changes
(2) Concavity and convexity of functions

The geometric meaning of the derivative of a function at a certain point

Is the slope of the tangent of the function curve at that point

Given that 1 of a minus 1 of B equals 1 of 2, find the value of AB of a-b

1/a-1/b=1/2
(b-a)/ab=1/2
ab=2(b-a)
ab/(a-b)
=[2(b-a)]/(a-b)
=[-2(a-b)]/(a-b)
=-2

If the positive △ ABC with side length of 2 is folded into a dihedral angle b-ad-c of 60 ° along the midline ad on the side of BC, then the distance from point d to ABC is

This problem can be solved by equal product method. The volume of Mitsubishi cone a-bcd = the volume of Mitsubishi cone d-abc

The vector a can be expressed as a = 2E1 + 3E under the base {E1, E2}. If a can be expressed as a = in (E1 + E2) + μ (E1-E2) under the base {E1 + E2, E1-E2}, then in=____ μ=_____

According to the meaning of the title: λ (E1 + E2) + μ (E1-E2) = 2E1 + 3e2
∴(λ+μ)e1+(λ-μ)e2=2e1+3e2
∴λ+μ=2,λ-μ=3
∴λ=2.5,μ=-0.5

As shown in the figure, in RT △ ABC, ∠ C = 90 °, D is a point on the edge of AC, de ⊥ AB is in E, de: AE = 1:2. Find SINB, CoSb, tanb

∵∵∵ a = ∵ a, ∵ AED = ∵ ACB, ∵ ABC ∵ ade, ∵ BC: AC = de: AE = 1:2, let BC = x, then AC = 2x, then AB = BC2 + ac2 = 5x, ∵ SINB = acab = 255, CoSb = bcab = 55x, tanb = ACBC = 2

If a is the bottom log (3 / 4) (a > 0 and a ≠ 1), find the value range of real number a
If a is the bottom log (3 / 4) 0 and a ≠ 1), the value range of real number a is obtained
The above topic is wrong

A is the base log (3 / 4) 0 and a ≠ 1)
1'0

As shown in the figure, it is known that the radius of ⊙ o is 5, the acute angle △ ABC is inscribed in ⊙ o, BD ⊥ AC is at point D, ab = 8, then the value of Tan ∠ CBD is equal to ()
A. 43B. 45C. 35D. 34

If B is used as the diameter BM of ⊙ o, and am is connected, then there are: ⊙ mAb = ⊙ CDB = 90 °, ⊙ M = ⊙ C; ⊙ MBA = ⊙ CBD; if O is used as OE ⊥ AB in E; in RT △ OEB, be = 12ab = 4, OB = 5; according to Pythagorean theorem, OE = 3; ⊙ Tan ⊙ MBA = oebe = 34; therefore, Tan ⊙ CBD = Tan ⊙ MBA = 34, so D is selected

If u = R, M = {x | x ≥ 1}, n = {x | x + 1 / (X-2) ≥ 0}, then Cu (m ∩ n)=
A.{x|x＜2} B.{x|x≤2} C.{x|-1＜x≤2} D.{x|-1≤x＜2}

From (x + 1) / (X-2) ≥ 0, we know that x ≤ - 1 or x > 2, the intersection with X ≥ 1 is x > 2, and the complement of the complete set of x > 2 is x ≤ 2, so we choose B