If A1, A2, A3 are known to be an arithmetic sequence, B1, B2, B3 are known to be an arithmetic sequence, and these six numbers are all real numbers, then the correct conclusion in the following four conclusions is () ① A1a3 may be established at the same time; ② B1 < B2 and B2 > B3 may hold simultaneously ③ If a1 + A2

If A1, A2, A3 are known to be an arithmetic sequence, B1, B2, B3 are known to be an arithmetic sequence, and these six numbers are all real numbers, then the correct conclusion in the following four conclusions is () ① A1a3 may be established at the same time; ② B1 < B2 and B2 > B3 may hold simultaneously ③ If a1 + A2

2. 4 is right. Choose B
If A1 < A2, the tolerance d > 0, then A2 must be less than A3
Take A1 = - 3, A2 = 0, A3 = 3, we can know that 3 is wrong
2, B1 = - 2, B2 = 4, B3 = - 8, right
4, B1 = - 2, B2 = 4, B3 = - 8, right

5 of () equals 0.8: () equals 3 of 4: () equals 1.2
Fill it in

(4 / 5) equals 0.8: (0.75) equals 3 / 4: (6 / 5) equals 1.2
I'm in the third year of junior high school. I'm sure I'm right,

What unit of weight is St? How to convert it into kilogram?
For example, weight (st): 13.08

Weight st = stone
1 stone = 6.35 kg
St = shipping ticket

It's hot in summer. There's a sprinkler on the street. It's a dream of cool water. Why do I feel hot when I stand in the place where I finish sprinkling?

It's cold water. It just touches the ground. The heat on the ground is absorbed and evaporated by the water. The heat you feel is the heat stored on the ground for a long time

How to convert kilovolt ampere to kilowatt
There are 28 pumping stations at all levels in a district, with a total installed capacity of 380900 kVA. How to convert KVA into kW

KVA is the unit of apparent power, kW is the unit of active power. If the power factor is known (assuming that all load power factors are the same), then s * cos Φ = P, where s is the apparent power, unit KVA, cos Φ is the power factor, P is the active power, unit kW. Or if the reactive power Q, unit kvar, then p can be obtained from S ^ 2 = P ^ 2 + Q ^ 2

Factorization of 3AB ^ 4-6ab + 3A

Original formula = 3A (b ^ 4-2b + 1)

Comparison of electric power between series and parallel circuits
In the series circuit, the electric power of r1.r2 is p1.p2, and the total power is P3. In the parallel circuit, it is p4.p5. Comparison: P1 and P2, P4 and P5, P1 + P2 and P3, P1 + P2 and P4 + P5

So P1 > P2
Parallel voltage equal P4

First simplify, then evaluate (3m-5m + 4Mn) - (2m-4n + 6MN)

You expand the brackets
(3M-5M+4MN)-(2M-4N+6MN)
=3M-5M+4MN-2M+4N-6MN
=-4M+4N-2MN

With regard to electric work and electric power, the following statement is correct ()
A. Electric work is a physical quantity that indicates how fast the current does work. B. an electric appliance with high electric power must do more work than an electric appliance with low electric power. C. The more work the current does through the conductor, the greater the electric power. D. in the same time, the more work the current does through the conductor, the greater the electric power

A. Electric work is the work done by the current, and electric power is the physical quantity that indicates the speed of work done by the current. B. if the electric power of the consumer is large, it means that the current does more work in the same time. This option does not mention whether the time is the same, so the work is not necessarily more. C. electric power is the amount of work done by the current in a second. This option does not mention the time. D. It is in line with the definition of electric power

If the spring is cut in half, what is its coefficient of elasticity
If a spring is cut in half, how does its coefficient of elasticity change?
If two springs are used in parallel, will their coefficient of elasticity be doubled?

The original coefficient is K
The elastic coefficient is 2K
The service factor of parallel connection is constant