In ABC triangle, a = 2bcosc, judge what triangle is

In ABC triangle, a = 2bcosc, judge what triangle is


According to the cosine theorem: COSC = (A & sup2; + B & sup2; - C & sup2;) / 2Ab a = 2bcosc
∴(a²+b²-c²)/2ab =a/2b
‖ B & sup2; = C & sup2; ∵ ABC triangle ‖ B = C
A triangle is an isosceles triangle



In the triangle ABC, it is known that a-square-c-square = AC root 3bC, and a, B, C are in equal proportion sequence, then a is obtained


a^2-c^2=ac-√3bc,b^2=ac
A ^ 2-B ^ 2-C ^ 2 = - √ 3bC
So cosa = (b ^ 2 + C ^ 2-A ^ 2) / (2BC) = √ 3 / 2
A=π/6



In △ ABC, a, B, C are in equal proportion sequence, and a & # 178; - C & # 178; = AC BC, find a and bsinb / C


a. If B and C are in equal proportion sequence, then:
b²=ac
Because: A & # 178; - C & # 178; = AC BC, then:
a²-c²=b²-bc
b²+c²-a²=bc
cosA=(b²+c²-a²)/(2bc)=1/2
A=60°
Bsinb / C [B & # 178; = AC, then: B / C = A / b]
=(a/b)sinB
=a(sinB/b)
=a(sinA/a)
=sinA
=√3/2



If LGA, LGB and LGC are equal difference sequence, then the relationship among a, B and C is equal


LGA, LGB and LGC form arithmetic sequence
2lgb=lga+lgc
lgb^2=lgac
b^2=ac
So it's an equal ratio sequence



When a moving object moves in a straight line, the average speed in 1s & nbsp; is 3m / s, the average speed in 2S & nbsp; and 3S & nbsp; is 6m / s, and the average speed in 4S & nbsp; is 5m / s, then the average speed of the moving object in 4S is 3m / s______ .


The average velocity in 1s & nbsp; is 3m / s, the average velocity in 2S and 3S & nbsp; is 6m / s, and the average velocity in 4S & nbsp; is 5m / s, so the displacement in 1s & nbsp; is 3M, the displacement in 2S is 6m, the displacement in 3S is 6m, the displacement in 4S is 5m, so the total displacement in the first 4S is: x = 3 + 6 + 6 + 5 = 20m, so the average velocity of moving object in 4S is. V = XT = 20ms, 4S = 5m / s, so the answer is: 5m / s



Using VB to program the sum of natural numbers from 1 to 100


dim i as integer
dim sum as integer
i = 1
Method 1
do while i 100
sum = sum + i
i = i + 1
loop
Method 3
do
sum = sum + i
i = i + 1
loop while i < 100



If no matter what the value of K is, x = - 1 is the solution of the equation (KX + a) about X, 2 = (- x-bk) \ - 3, find the value of ab


Substituting - 1 into! Gets: (A-K) / 2 = (1-bk) / - 3
3A-2BK=-2+3K
So 3A = - 2
-2BK=3K
A=-2/3 B=-3/2
AB=1



The distance from a point on the number axis to the origin is 5 and half, so what is the number represented by this point?


If there is a point on the number axis whose distance from the origin is 5 and half, then the number represented by this point is 5 and half or - 5 and half



A mathematical problem about proportion!
In order to build a teaching building in a primary school, cement, yellow sand and stones need to be mixed into concrete according to the ratio of 2:3:5. Now, according to the needs of building, 2.7 tons of yellow sand is prepared, and how many tons of cement and stones need to be prepared?
Don't use the equation. It seems that we need to add up the 2:3:5 first, and then we don't know how to calculate~


Let cement be x tons of cement: 2 / 3 = x / 2.7 x = 1.8 tons
Suppose that the stone is y ton stone: 3 / 5 = 2.7 / y, y = 4.5 ton



The product is______ The two numbers of are reciprocal______ .


Two numbers whose product is 1 are reciprocal to each other