Find the fourth order determinant a 100 - 1 B 100 - 1 C 100 - 1 D

Find the fourth order determinant a 100 - 1 B 100 - 1 C 100 - 1 D

Solution: D = R 1 + Ar 201 + AB a 0-1 B 100 - 1 C 100 - 1 Dr 1 + (1 + AB) r 300 a + C + ABC 1 + AB-1 B 100 - 1 C 100 - 1 Dr 1 + (c + ABC) r 400 01 + AB + D (a + C + ABC) - 1 B 100 - 1

ABC is three real numbers which are not equal to each other. The necessary and sufficient condition for finding a ^ 3 + B ^ 3 + C ^ 3 > = 3ABC
A ^ 3 is the cube of A
>=Denotes greater than or equal to

Find the area s of the plane figure enclosed by the curve & nbsp; y = x2-2x, y = 0, x = 1, x = 3, and find the volume V of the body of revolution after the plane figure rotates around the Y axis

The plane figure of this problem is as follows: then the area of plane figure s = ∫ & nbsp; 21 (0 − y) DX + ∫ & nbsp; 32 (Y − 0) DX = ∫ & nbsp; 21 (2x − x2) DX + ∫ & nbsp; 32 (x2 − 2x) DX = [x2 − 13x3] 21 + [13x3 − x2] 32 = [(4 − 83) − (1 − 13)] + [(9 − 9) − (83 − 4)] = 2 the plane figure revolves around y

According to the regulations, the car should pass through the tunnel at a slow speed. Before passing through the tunnel, a car reduces its speed from 25m / s to 10m / s, and then passes through the 100 meter tunnel at a constant speed
According to the regulations, cars should slow through the tunnel. Before passing through the tunnel, a car reduces its speed from 25m / s to 10m / s, and then passes through the 100 meter tunnel at a constant speed. It takes 15 seconds to calculate the acceleration when the car decelerates

The time of uniform velocity stage is t = s / V, t = 10s
Then the deceleration phase takes 5S, and because a = △ V / T, a = 15 / 5 = 3m / S ^ 2 is obtained

Simple calculation of 0.65 plus 0.35 times 1.8

0.65+0.35×1.8
=0.65+0.35×(1+0.8)
=0.65+0.35×1+0.35×0.8
=0.65+0.35+0.28
=1+0.28
=1.28

Given x-2y + 4Z = 0; 2x-3y + 5Z = 0, find the value of X: Y: Z

We can get x = 2y-4z from the original, y = 3Z from the second, and x = 2Z from the original

The perimeter of the rectangle is 50 decimeters, the width is 2 / 3 of the length, and the area of the rectangle is () square decimeters!

Length + width = 50 △ 2 = 25 decimeters
Length = 25 ÷ (1 + 2 / 3) = 15 decimeters
Width = 25-15 = 10 decimeters
Area = 15 × 10 = 150 square decimeters

X ^ 3 + X-6 is the factor of polynomial 2x ^ 4 + x ^ 3-ax ^ 2 + BX + A + B-1, find a =?, B =?

(x^3+x-6)(2x+c)=2x^4+x^3-ax^2+bx+a+b-1
cx^3=x^3,c=1
2x^2=-ax^2,a=-2
-6c=a+b-1=-6
b=-3
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If x and y satisfy the constraint condition x + y ≥ 1 x − y ≥ 12 x − y ≤ 2, and the objective function z = ax + 2 y only obtains the minimum value at point (1,0), then the value range of real number a is ()
A. （-1，2）B. （-4，2）C. （-4，0]D. （-2，4）

When a ＞ 0, the slope of AX + 2y-z = 0 is k = - A2 ＞ KAC = - 1, a ＜ 2. When a ＜ 0, k = - A2 ＜ KAB = 2A ＞ - 4

When 27 is divided into the sum of several different prime numbers, to maximize the product of the prime numbers, these prime numbers are______ ．

According to the analysis, these prime numbers are 2, 5, 7 and 13 respectively, so the answer is: 2, 5, 7 and 13