For the formula y = KX + B, when x = 1, y = 3, when x = - 2, y = 4, then k = (), B = () For the formula y = KX + B, when x = 1, y = 6; when x = 2, y = 8, then k = (), B = ()

For the formula y = KX + B, when x = 1, y = 3, when x = - 2, y = 4, then k = (), B = () For the formula y = KX + B, when x = 1, y = 6; when x = 2, y = 8, then k = (), B = ()

Y = log0.2 (4x-3) under the root sign, find the definition field

hi !
First, for log0.2 (4x-3)
4x-3>0
Then x > 3 / 4
For the root sign
Log 0.2 (4x-3) ≥ 0
Then 0 ＜ 4x-3 ≤ 1
In conclusion, 3 / 4 < x ≤ 1
The domain of definition is (3 / 4,1]

Mathematical Olympiad in grade five of primary school
1. The five cards are written with numbers: 0, 0, 1, 2 and 3. They can be used to form many different five digit numbers. What is the average of all these five digit numbers
I'm going to use it today. Before 10 p.m., I've also listed 72 numbers, but I'm not going to add them up one by one to work out the answer. There must be a simple way. Thank you

First decide where the two zeros are. 0 can't be in the first place, so there are four positions for 0, so there are six ways to put 0
Then 1, 2 and 3 can be put in the other three positions, so there are six methods
The total number of methods is 6 × 6 = 36
For each digit, find the average of the 36 numbers in that digit
Ten thousand:
The three numbers 1, 2 and 3 can all be in ten thousand bits
There are 12 numbers with 10000 bits of 1, 2 and 3 respectively, so the average number of 10000 bits is 2
Thousand:
Considering the positions of the two zeros, there are six pendulum methods for the two zeros. Three of them put one of the zeros in the thousand position, and the other three are that the two zeros are not in the thousand position. Therefore, half of the numbers (18) have the thousand position of 0, and the other half (18) have the thousand position of 1, 2 and 3. Due to the symmetry of the three numbers 1, 2 and 3, there are six thousand positions of 1, six thousand positions of 2 and six thousand positions of 3, So the average number of thousand bits is 6 × (1 + 2 + 3) / 36 = 1
Hundred, ten, individual:
Because the rules for the number of hundred, ten, and individual positions are the same as those for thousand positions (different from ten thousand positions, because ten thousand positions cannot be zero), the average number is also 1
So the average of these 36 numbers is 21111

What is eight minus two

10

Fractional multiplication and division, especially the calculation problem, at least 2 steps, urgent
1. Simplification: 2-4x of 4x & # 178; - 1 △ 4x of X & # 178; + 4x + 1
2. The result is ()
A、1 B、a C、1/a D、1/a²
3. - M & # 178; the result is ()
A. Square B of N, cubic C of - m, fourth D of - m, and - n
4. Calculation:
（1）9a²x/-by²÷b²y²/-6ax （2）12xy/5a÷（-8x²y）
(3)a/a²b-b÷a²b/a²--a （4）x²-8x+16/4-x²÷16-x²/4+4x+x²
(5) (A & # 178; B / - C) · (C & # 178; / - AB) cubic (BC / a) quartic (6) M-M & # 178 / / M & # 178; - 1 △ M / M-1 · (M + 1 / m-1) square
（7）a²-4/a²+4a+4÷（a-2）*a²-2a+1/a-1
5、（1）（a/b）²÷（2a²/5b²）*a/5b （2）4x²-4xy+y²/2x+y÷（4x²-y²）
Note: all / here represent the fractional line

1、（2x+1）（2x-1）/2（1-2x）× x/（2x+1）² =-x/4x+22、A3、-n²/m²×m³/n²×n²/m=-n D4、1）54a³x²/b³y4 2）-3/10ax 3）1/b²（a+1...

How much is 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11. + 1000?

﹙1+1000﹚×1000÷2=500500

An increase of 40% is equal to 3.5. What's three fifths of it?

This number is 3.5 / (1 + 40%) = 2.5
Three fifths of it is 2.5 * 3 / 5 = 1.5

English translation
Let's not worry about our problems. Let's face the challenges instead!

Let's not worry about our problems, let's face the challenge instead of worry. Instead, instead is to replace the worry mentioned above

How to calculate the average year and leap year?

The average year is 365 days, and the leap year is 366 days
Accurate calculation method of leap year in Gregorian calendar (365 days, 5 hours, 48 minutes, 45.5 seconds in a regression year)
① The ordinary year can be divided by 4 and cannot be divided by 100 is leap year. (for example, 2004 is leap year, 1901 is not leap year). ② the century year can be divided by 400 is leap year. (for example, 2000 is leap year, 1900 is not leap year)
③ For a year with a large number, if 3200 can be divided and 172800 can be divided, it will be a leap year. For example, 172800 is a leap year, and 86400 is not a leap year (because although 3200 can be divided, 172800 cannot be divided) (this is calculated according to 5h48'45.5 "of 365 days in a regression year)

Under what circumstances is one plus one equal to three

In case of miscalculation