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The solution of inequality about X: ax ^ 2-2 (1 + a) x + 4 > 0
(1) When a > 0, the opening of parabola is upward, the solution of ax ^ 2-2 (1 + a) x + 4 = 0 is X1 = 2, X2 = 2 / A
The solution of 0 is x2 / A
a> The solution of 2 / A0 is x > 2 or x = 1
Inequality (AX-1) (x ^ 2-x-2) > 0
Inequality (AX-1) · (x ^ 2-x-2) > 0 process
When a = 0 - 1 (x ^ 2-x-2) > 0, X ∈ (- 1,2)
When a ≠ 0, factorization results in (AX-1) (X-2) (x + 1) > 0
X = 1 / A or 2 or - 1 is zero
-1
LIM (x tends to 0) [(sin2x) ^ 2] / x ^ 2 =?
Using Equivalent Infinitesimal Substitution
LIM (x tends to 0) [(sin2x) ^ 2] / x ^ 2
=LIM (x tends to 0) (2x) ^ 2 / x ^ 2
=LIM (x tends to 0) 4x ^ 2 / x ^ 2
=4
It is known that a of B is one-third, and 3a plus 2b is three-thirds. What are a and B equal to
a/b=1/3
3a=b
3a+2b=3/2
b+2b=3/2
3b=3/2
b=1/2
3a=1/2
a=1/6
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I have four classes in the morning
I have four lessons in the morining.
How many miles is a kilometer?
It seems that (length unit and weight unit) are not the same, so one kilometer is not equal to two Li, because now there is no saying of Li. Li is what we usually say. In the book, one kilometer is equal to one thousand meters! I believe many people think that one kilometer is equal to two Li. That's wrong. It's different from the weight unit. It can't be the same as one kilogram is equal to two Jin
One kilometer is two miles
1×2＋2×3＋3×4＋4×5＋...＋98×99＋99×100=?
To decompose and sum, the following formula must be used: 1 ^ 2 + 2 ^ 2 + 3 ^ 2 +... + n ^ 2 = n (n + 1) (2n + 1) / 6 1 * 2 + 2 * 3 + 3 * 4 + 4 * 5 + + 98*99+99*100=1*(1+1)+2*(2+1)+3(3+1)+4(4+1)+…… +98(98+1)+99(99+1) =(1^2+1)+(2^2+2)+(3^2+3)+(4^2+4)+…… +(...
What do two English words mean
1、Tehnical Author
2、Shipping Receiving
It should be two occupations, but I didn't know what it was after looking it up in the dictionary
thank you.
1. Technical author should be the chief editor of technical author
2. Shipping receiving freight management
The sum of the first n terms of the arithmetic sequence {an} is Sn, and S4 = - 62, S6 = - 75
Find the value of | A1 | + | A2 | + | A3 | +. + | an |
Let z = XLN (XY) find DZ
This is to find the total differential of an explicit function. We can directly find the differential on both sides! Then we can solve it according to DUV = VDU + UDV. For the obvious existence of partial derivative, we can also directly find the partial derivative, and then substitute it into the expression of total differential
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