If we change the quadratic equation 2x + 3y-4 = 0 to y = KX + m, then m-k=______ ．

If we change the quadratic equation 2x + 3y-4 = 0 to y = KX + m, then m-k=______ ．

∵ 3Y = - 2x + 4, ∵ y = - 23 + 43. Then M = 43, k = - 23 ∵ m-k = 43 + 23 = 2

Change the quadratic equation 2x + 3Y = 25 into the form of y = KX + m and write the value of K, M

2x + 3y = 25 ( y=kx+m )
3Y = - 2x + 25 (leave y, all others move to the right)
Y = (- 2 / 3) x + 25 / 3
k = (-2) / 3 m = 25 / 3

As shown in the figure, am cuts ⊙ o at point a, BD ⊥ am at point D, BD intersects ⊙ o at point C, OC bisects ⊙ AOB. Calculate the degree of ⊙ B

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If the image of inverse scale function y = 2m + 1 of X passes through point a (1. - 3), what is the value of M

y=(2m+1)/x
Substituting into point A: - 3 = (2m + 1) / 1
2 m + 1 = - 3
m=-2

If the equation X-8 / (X-7) - 11 / (7-x) = 8 has an increasing root, then the increasing root is x = 7, right

Increasing root is the root that makes this question meaningless. According to the above question, only when x = 7 is meaningless, so increasing root is x = 7, which is very correct

T (x) = f (x) + G (x), where f (x) is the positive proportion function of X, G (x) is the inverse proportion function of X, and t (1 / 3) = 16, t (1) = 8, find the analytic expression of T (x)

Let f (x) = ax, G (x) = B / X
Because t (x) = f (x) + G (x) and t (1 / 3) = 16, t (1) = 8
So 1 / 3A + 3B = 16, a + B = 8
The solution is a = 3, B = 5
So t (x) = 3x + 5 / X

1 minus 1 in 100 times 1 minus 1 in 101. How much is 1 minus 1 in 2008?

99 out of 100 by 101 out of 100. By 2007 out of 2008 is 99 out of 2008

Enumerating the following set of square x-4x + 3 = 0
1. The set of the following of X square-4x + 3 = 0 2. The set of the intersection of the square-2 of parabola y = x and the line X-Y = 0

X | x ^ 2-4x + 3 = 0} is OK, you can also solve two, written as X belongs to {x1, X2} form, the shape of the parabola is the same as the parabola y = x square, and the axis of symmetry is a straight line x = 1 / 2, intersecting with the Y axis at the point (0. - 1), the shape of a parabola is the same as y = X2 (square), and the axis of symmetry is a straight line x = 1 / 2, intersecting with the Y axis at the point (0, -1) Let the parabola be y = (x-a) ^ 2 + B, expand y = x ^ 2-2ax + A ^ 2 + B  axis of symmetry x = a = 1 / 2, then substitute (0, - 1) point into b = - 5 / 4, so y = x ^ 2-x-1

20%x+12=0.5x

20%x+12=0.5x
(20% to 0.2)
0.2x+12=0.5x
(move item again)
0.5x-0.2x=12
0.3x=12
x=12÷0.3
x=40

Add symbols such as "addition, subtraction, multiplication and division" between the five halves to make the equations equal to 0, 1, 2, 3, 4, 5 and 6 respectively

1 / 2 * (1 / 2 - 1 / 2 + 1 / 2 - 1 / 2) = 01 / 2 * (1 / 2 + 1 / 2 + 1 / 2 + 1 / 2) = 1 (1 / 2 + 1 / 2) * (1 / 2 / 1 / 2 / 1 / 2) = 2 (1 / 2 + 1 / 2) + (1 / 2 / 1 / 2 / 1 / 2) = 3 (1 / 2 + 1 / 2 + 1 / 2 + 1 / 2) / 1 / 2 = 4 (1 / 2 + 1 / 2 + 1 / 2) / (1 / 2 * 1 / 2) = 6 how to equal 5, give it to