2.5 times (x-16%) = 1.8 to solve the equation

2.5 times (x-16%) = 1.8 to solve the equation

2.5 times (x-16%) = 1.8
x-16%=1.8÷2.5
x=0.72+0.16
x=0.88

Simplification: 1. X & # 178; - 4 / X & # 178; + 4x + 4 ÷ (X-2) × (x + 1) (x + 2) / X-2
2.1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3)
3.X-9Y/6XY²-X+3Y/9X²Y

1.=...
2.=1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)=1/x-1/(x+3)=3/x(x+3);
3.=(2Y-9)/6X²Y

Is there any rule about how to move the moving term in the equation of one variable and one degree

Adding (or subtracting) the same number or the same integral on both sides of the equation is equivalent to changing the sign of some terms in the equation and moving them from one side of the equation to the other side. This deformation is called term shifting, In order to change the equation into the form of AX = B, we need to merge the similar terms, but they are not on the same side of the equal sign. How to merge them? We can use the basic properties of the equation to subtract 2 from both sides of the equation, and then subtract 7x from both sides of the equation, In this way, we can get: 5x-7x = - 8-2, and then merge the similar terms. Here, 2 changes the sign and moves to the right of the equation, 7x changes the sign and moves to the left of the equation. This kind of deformation is equivalent to moving one term of the equation from one side to the other side after changing the sign, This kind of deformation is called term shifting. Let's first look at the above cited example: solve the equation 5x + 2 = 7x-8.in order to change the equation into the form AX = B, the unknown term can be moved to the left of the equation, the known term can be moved to the right of the equation, or the unknown term can be moved to the right of the equation, and the known term can be moved to the left of the equation, We can get the following two solutions. Solution 1: transfer the term, get 5x-7x = - 8-2, merge the similar term, get - 2x = - 10, coefficient 1, get x = 5. Solution 2: transfer the term, get 2 + 8 = 7x-5x, merge the similar term, get 10 = 2x, coefficient 1, get x = 5. (finally, check the root by oral calculation). Comparing the two solutions, the unknown term moves in different directions, but both can reduce the equation to the simplest form AX = B, Then we can get the solution of the equation. For example 2, we can solve the equation 6-2x = 5-3x.for example 2, we can transfer the term to get - 2x + 3x = 5-6, and combine the similar terms to get x = - 1.for example 2, we can see that the term to be transferred should change the sign, and the term not to be moved should not change the sign!

In the derivation formula, where -- (logax) '= 1 / (x * LNA) LNA is a constant?

Yes, LNA is a constant
Change the bottom first:
logax=lnx/lna
So (logax) '= (LNX / LNA)' = (1 / LNA) (1 / x) = 1 / (x * LNA)

Factorization of a ^ 3-4A

a^3-4a=a(a^2-4)=a(a+2)(a-2)

The absolute value of inequality-2x-3 is less than or equal to 4

|-2X-3|

The function f (x) = x ^ 2 - (K-2) x + K ^ 2 + 3K + 5 has two zeros
1) If the two zeros of the function are - 1, - 3, find the value of K
(2) If the two zeros of the function are a, B. find the value range of a ^ 2 + B ^ 2

Take the two zero values to the original function, get k ^ 2 + 4K + 4 = 0 and K ^ 2 + 6K + 8 = 0, get k = - 2 or K = - 4, bring into the original equation k = - 4, so k = - 2
A + B = (K-2) / 2 ab = k ^ 2 + 3K + 5 is obtained from the original equation
a^2+b^2=(a+b)^2-2ab=((k-2)/2)^2-2(k^2+3k+5)
The function has two zeros △ > 0, and then it is brought into △ to find the range of K. The answer to (2) is obtained by substituting the above formula
Please do it yourself in the back^-^

It is known that the quadratic function y = x2-2kx + K2 + K-2. (1) when the value of the real number k is, the image passes through the origin

Substitute the origin into 0 = k * k + K-2 (K + 2) * (k-1) = 0, k = 1, k = - 2

The sum of each digit in a three digit number is 16, and the ten digit number is the sum of the single digit number and the hundred digit number

Three equations can be listed according to the meaning: x + y + Z = 16, y = x + Z, (100z + 10Y + x) - (100x + 10Y + Z) = 594, which can be solved to x = 1, y = 8, z = 7, so the original number is 187

Decomposition factor (with process), X2 power - 2ax-3a2 power, X2 power - 2 root sign 2x-3, X3 power + X - (A3 power + a)

The first x ^ 2-2ax-3a ^ 2 = x ^ 2-2ax + A ^ 2-A ^ 2-3a ^ 2 = (x-a) ^ 2-4a ^ 2 = (x-a) ^ 2 - (2a) ^ 2 = (x-a + 2a) * (x-a-2a) = (x + a) * (x-3a) the second x ^ 2-2 √ 2x-3 = x ^ 2 - [(√ 2 - √ x) ^ 2-2-x] - 3 = x ^ 2 - (√ 2 - √ x) ^ 2 + X-1 = (x + √ 2 - √ 3) * (x - √ 2 + √ 3) + X-1 the third x ^ 3 + X - (...)