5 out of 8 plus 4 out of 7 is 3 out of 4

5 out of 8 plus 4 out of 7 is 3 out of 4

X = 2 / 7

The line L passing through the point m (- 2,0) intersects the ellipse at two points p1p2. The midpoint of the line p1p2 is p. let the slope of the line l be K (K ≠ 0) and the slope of the line OP be K2
Find the value of K1 and K2

Your problem condition is not enough, your elliptic equation is? The result should not be good, find out the specific value of K1, K2, but can find out the product of K1, K2

Conversion between 8421BCD code and decimal number
（100101111000）8421BCD
(19.7)10

（100101111000）8421BCD=（1001 0111 1000）8421BCD=（978）10
(19.7)10=（0001 1001 . 0111）8421BCD=（11001. 0111）8421BCD

1+（—2）+3+（—4）+5+（—6）+.+2011+（—2012）+2013=

There are 2013 addends
In the first 2012 addends, the adjacent two are divided into a group
They were divided into 2012 △ 2 = 1006 groups
The sum of each group is - 1
1+（—2）+3+（—4）+5+（—6）+.+2011+（—2012）+2013
＝(-1)×1006＋2013
＝2013－1006
＝1007

Definition: if the function y = f (x) exists x0 (a < x0 < b) in a given interval [a, b] in the domain of definition, satisfying f (x0) = f (b) − f (a) B − a, then the function y = f (x) is called the "mean function" on [a, b], and x0 is its mean point. For example, y = X4 is the mean function on [- 1, 1], and 0 is its mean point. (1) judge whether the function f (x) = - x2 + 4x is on the interval [0, 9] Is it an average function? If so, find out its mean value; if not, explain the reason; (2) if the function f (x) = - x2 + MX + 1 is the mean value function on the interval [- 1,1], try to determine the value range of real number M

(1) From the definition, when the equation - x2 + 4x = f (9) − f (0) 9 − 0 of X has a real root in (0, 9), the function f (x) = - x2 + 4x is an average function in the interval [0, 9]. By solving - X2 + 4x = f (9) − f (0) 9 − 0 {x2-4x-5 = 0, we can get x = 5, x = - 1. And - 1 ∉ (0, 9), x = 5, so the function f (x) = - x2 + 4x is an average function in the interval [0, 9], and 5 is its average point. (2) ）Function f (x) = f (x) = f (x) (f (x) = f (x) = -x2 + MX + 1 is the average value function in the interval [-1, 1] 1 [-1, 1], and the equation for X is the equation-x2 + MX + MX + 1 = f (1) {x (x + MX + 1 = f (x) = f (x) (f (x) = f (x) (f (x) = f (x) (f (x) = f (x) = x + MX + MX + 1 = f (x + 1 = f (x + MX + 1 = f (x + 1) = f (1) {∉ (1,1,1) ∉ (- 1,1,1,1) ∉ (- 1,1,1) ∉ ∉ (1,1) ∉ (1,1) 8713; ∉ (1,1) ∉ ∉ (1) 1

What is 1 + 2 + - 3-4 + 5. + 2005 + 2006-2007-2008

1+（2-3）+（-4+5）+...+（-2004+2005）+（2006-2007）-2008
1-1+1-1+1-1.-2008
There are 2008 numbers from 1 to 2008, 2006 numbers from 2 to 2007, and - 1 for 2006 / 2 = 1003
So the whole value is - 1
1-1-2008
The answer is - 2008

Point P jumps from point a one unit length from the origin to the origin, and jumps to the end point A1 of O for the first time,
Point P jumps from point a one unit length away from the origin to the origin. For the first time, it jumps to the end point A1 of O, for the second time, it jumps from point A1 to the midpoint A2 of OA1, and for the third time, it jumps from point A2 to the end point A3 of oa2. If so, what is the distance from the point to the origin o after the eighth jump?

One eighth: one fourth equals one tenth: X one third x + one fourth x equals 21

One eighth: one fourth equals one tenth: X
x=1/4x1/10÷1/8
x=1/5
One third x + one fourth x equals 21
7/12x=21
x=21÷7/12
x=36
If you don't understand this question, you can ask,

If the vector group A1, A2, A3 is linearly independent, find the linear correlation of a1 + A2, A2 + a3, a3-a1

Suppose that a1 + A2, A2 + a3, a3-a1 are linearly independent, then there are K1, K2, K3 with all zeros
k1(a1+a2)+k2(a2+a3)+k3(a3-a1)=0
(k1-k3)a1+(k1+k2)a2+(k2+k3)a3=0
Because the vector group A1 A2 A3 is linearly independent, K1-K3 = 0, K1 + K2 = 0, K2 + K3 = 0
K 1, K 2 and K 3 are not all zero, which contradicts the hypothesis
So a 1 + a 2, a 2 + a 3, a 3 - a 1 linear correlation

With the help of calculator or computer, the approximate solution of the equation x ^ 3 + 5 = 6x ^ 2 + 3x can be obtained by dichotomy
Dear prawns, I really have no choice but to turn to you for help. If I can't do the above questions, I can also tell me the interval of X. thank you very much!

Let f (x) = x ^ 3-6x ^ 2-3x + 5, one between (0,1), the same as above
The other one is between (- 2, - 1)
I'm afraid you've only half solved the problem after all your hard work