Given x + y = 4, / X / + / Y / = 7, then the value of X-Y is(

Given x + y = 4, / X / + / Y / = 7, then the value of X-Y is(


x+y=4,/x/+/y/=7
So, XY is different
x=5.5,y=-1.5
Or X -- 1.5, y = 5.5
So, X-Y = 7 or - 7



Given that x + y = 4, | x | + | y | = 7, then the value of X-Y is______ .


X + y = 4, | x | + | y | = 7, x = 112, y = - 32 or x = - 32, y = 112, then the value of X-Y is, ± 7, so the answer is: 7 or - 7



In order to select four different subsets from the subset of the set u = {a, B, C, D}, the following two conditions must be satisfied simultaneously: 1
Four different subsets are selected from the subset of the set u = {a, B, C, D}, which need to satisfy the following two conditions at the same time
1. U must be chosen
2. For any two selected subsets A and B, a must be included in B or B in a
There are several different ways to choose, 2010 Shanghai college entrance examination question answer is 36 how to calculate?


Four different subsets, including & ∅ u, are left with only two subsets u = {a, B, C, D}. Except for & ∅ u, there are 14 subsets left. For any two selected subsets A and B, there must be a contained in B or B contained in acase 1. If one subset contains one element, and the other subset contains two or three elements with one element



How to solve the equation of 5x-2 * (20-x) / 2 = 64?


5X-2*(20-X)/2=64
5x-20+x=64
5x+x=20+64
6x=84
x=14



Move only one matchstick to make the equation true. One third times one half equals seven eighths


1/3*7/2=7/6



Equation 1 / 7 [1 / 5 (3 / x + 2 + 4) + 6] = 1
One third of X + 2 is one term and + 4 is another term


1 / 7 [1 / 5 (3 / x + 2 + 4) + 6] = 1
1 / 5 (3 / x + 2 + 4) + 6 = 7
1 / 5 (3 / x + 2 + 4) = 1
3 / 3 x + 2 + 4 = 5
3 of X + 2 = 1
x+2=3
x=1



How to calculate sin180? Sin0


sin0=0,sin180=-sin(180-180)=0



How to solve a math equation problem in the first semester of junior high school: 1 / 5 (x + 15) = 1 / 2-1 / 3 (X-7)
Remove the denominator and get 6 (x + 15) = 15-10 (X-7)
Remove brackets to get 6x + 90 = 15-10x + 70
Move to merge similar items and get 16x = - 5
Divide both sides of the equation by 16 to get x = - 5 / 16
Excuse me: why does the denominator get 6 (x + 15) = 15-10 (X-7)? Where does 6 come from? What are the following steps? Please explain


The least common multiple of 2,3,5 is 30, so if you multiply 30 by two meters at the same time, you can remove all denominators in one step, and then you can get the formula
6X + 90 = 15-10x + 70 the next step should be to merge the similar items, move 10x to the left to add 10x 6x + 10x + 90 = 15 + 70, and then change the left + 90 to the right to subtract 90, so that 16x = 15 + 70-90
16x=85-90
16x=-5
Then divide both sides by 16 to get x = - 5 / 16
——————End
Do you understand? If you understand, please accept it. If you don't understand, you can ask me



Xiao Jun read a story book. On the first day, he read 13% of the whole book. On the second day, he read 7% of the whole book. On the third day, he began to read 86 pages. How many pages does the book have?


Whole book = (86-1) / (13% + 7%) = 425 pages



As shown in the figure, in the plane rectangular coordinate system, a (1,1,) B (- 1,1) C (- 1, - 2) d (1, - 2) takes a length of 2012 units and has no
As shown in the figure, in the plane rectangular coordinate system, a (1,1,) B (- 1,1) C (- 1, - 2) d (1, - 2) fix one end of a thin line with length of 2012 units and no elasticity (the thickness of the line is ignored) at point a, and wind it around the edge of the quadrilateral ABCD according to the rule of a --- B --- C --- D --- a ·······, then the coordinates of the point at the other end of the thin line are: & nbsp; & nbsp; & nbsp; &A. (1, - 1) & nbsp; & nbsp; B. (- 1,1) & nbsp; & nbsp; C. (- 1, - 2) & nbsp; & nbsp; D. (1, - 2) & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; for help


Option B is correct! From the meaning of the question, it can be seen that the length of the thin wire fixed at point a and circled by a --- B --- C --- D --- A is 2 * (2 + 3) = 10 unit length, while 2012 = 2010 + 2 = 201 * 10 + 2. That is to say, the thin wire with the length of 2012 unit length can be circled by a --- B --- C --- D --- a