Is function x plus 1 / 2 minus 1 equal to function x plus 1?

Not equal to

Finding the minimum value of the function y = SiN x 1 / 2 plus cos x 2 / 2

Let sin square x = a, then y = 1 / A + 2 / (1-A), the range of a is [0,1]; for y, find the root of derivative, A1 = (root 2) + 1, A2 = 1 - (root 2); get the monotonicity in the domain, [0, A2] increases and [a2,1] decreases; if the minimum value is taken in a = A2, bring it in, get the minimum value of Y as (root 2) + 1 divided by (root 2) - 1;

Function f (x) = 2cosxsin (x + the third) - root 3 times sin square x + sinxcosx to find the minimum value of F (x) and point out the set of X (write the following steps)

Original formula = 2cosx (half SiNx + Half Root sign three cosx) - root three times sin square x + sinxcosx
=Sinxcosx + radical three (square of cosx) - radical three (square of SiNx) - sinxcosx
=Root sign three cos2x
Let 2x = pie + 2K pie and K belong to Z
We get x = half school + K school and K belongs to Z
Then, if x belongs to the set X = two-thirds + K and K belongs to Z
FX has a root sign three with a negative minimum

Let K be an integer and the solution of the equation KX = 6 + X is a natural number to find the value of K

If x is 1, then K is 7
If x is 2, then K is 4
If x is 3, then K is 3
If x is 4, the value of K is not an integer
If x is 5, the value of K is not an integer
If x is 6, then K is 2
If x is 7, the value of K is not an integer
It seems that's all

A and B two barrels of oil, pour 10% of a barrel of oil into B barrel, then the weight of two barrels of oil is equal, the original weight of B barrel of oil is 90% of B barrel of oil

No
Let a be x and B be y
Then 0.9x = y + 0.1X
y=0.8x
So the weight of B barrel oil is 80% of a barrel oil
But your question here is: the original weight of B barrel of oil is 90% of B barrel of oil
I don't know if you have the wrong number
x=5y/4=1.25y
Now B barrel oil is y + 0.125y = 1.125y
125 Y / (1.125 y) is about 88.9%
It's still wrong

Quadratic function y = x2 + MX + N, if M = n, then its image must pass through the point_____

Y = x2 + MX + N, if M = n,
Y=x^2+mx+m,
y-x^2=m(x+1),
When m = 0,
X+1=0,Y-X^2=0,
X=-1,Y=1,
The quadratic function y = x2 + MX + N, if M = n, then its image must pass through the point (- 1,1)

Five out of nine students in the school chorus are girls. There are 30 girls. How many boys are there?

There are 54-30 boys = 24

When a + B + C = 0, a & sup2; + B & sup2; + C & sup2; = 1, find the following values BC + Ca + ab=
We need to be comprehensive

a+b+c=0
(a+b+c)^2=0
a^2+b^2+c^2+2ab+2bc+2ca=0
1+2ab+2bc+2ca=0
2ab+2bc+2ca=-1
2(ab+bc+ca)=-1
ab+bc+ca=-1/2

In the first semester, there are 300 girls in grade five. In this semester, the number of boys and girls increases by 1 / 25 and 1 / 20 respectively. How many boys and girls are there in grade six this semester

Suppose there are x boys, then girls are (300-x)
(1 / 25) x + (1 / 20) (300-x) = 13
Simplified: x = 200 (people)
300-x = 300-200 = 100 (person)
There are 200 boys and 100 girls
Using binary linear equation
Let male be x and female be y
Formula x + y = 300.1
1 / 25 * x + 1 / 20 * y = 13. 2 for y, y = 300-x
Then substitute: 1 / 25 * x + 1 / 20 * 300-x = 13
x=200
Female: 300-200 = 100
A: 200 boys and 100 girls

30 divided by X + 25 = 85 solved by equation

Divide 30 by X + 25 = 85 and multiply both sides of the denominator by X
We get 30 + 25X = 85x
The solution is x = 0.5 (1 / 2 half)
need wheel cleaner toast thick
You need a wheel cleaner to bake (bread) thick

Is function x plus 1 / 2 minus 1 equal to function x plus 1?