Just use the number 8 to make up five numbers and fill in the box below to make the formula true______ ﹢______ ﹢______ ﹢______ ﹢______ =1000.

Just use the number 8 to make up five numbers and fill in the box below to make the formula true______ ﹢______ ﹢______ ﹢______ ﹢______ =1000.


According to the stem analysis can be: 888 + 88 + 8 + 8 + 8 = 1000, so the answer is: 888; 88; 8; 8; 8



The solution of equation 9 ^ X-6 * 3 ^ X-7 is


9^x-6*3^x-7=0
3^x=7
3 ^ x = - 1 (rounding off)
x=log3(7)



(1 / 2) evaluation, 1. Sin10sin30sin50sin70 2. (2cos10-sin20) / cos20 3. (1 + cos20) / 2sin20


(2cos10-sin20)/cos20=[2cos(30-20)-sin20]/cos20
=(2cos30cos20+2sin30sin20-sin20]/cos20
=(2*√3/2*cos20+2*1/2sin20-sin20)/cos20
=(√3cos20+sin20-sin20)/cos20
=√3cos20/cos20
=√3



How to solve the equation 4 (3.8 + x) divided by 2 = 20


4 (3.8 + x) divided by 2 = 20
2(3.8+X)=20
3.8+X=10
X=6.2



It took 380 meters to build a canal in four days. According to this calculation, it can be completed in another seven days. How long is the canal? (limited proportional solution)


Suppose the length of this canal is x km, from the meaning of the title: 380:4 = x: (4 + 7) & nbsp; & nbsp; & nbsp; 4x = 380 × (4 + 7) & nbsp; & nbsp; & nbsp; 4x = 380 × 11 & nbsp; & nbsp; & nbsp; & nbsp; 4x = 4180 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 1045 A: the length of this canal is 1045 km



If the point m [3,1-2a] is symmetric about X axis in the fourth quadrant, then the value range of a is?


According to the characteristics of each quadrant, the point about X-axis symmetry in the fourth quadrant should be in the first quadrant, so 1-2a should be greater than 0, so a is less than 1 / 2



How much is 5.4 yuan,


10 cents, 100 cents, 5.4 cents is 540 cents



Ellipse x square / M + y square = 1 the value range of real number m with focus on Y axis


X square / M + y square = 1
The focus is on the y-axis
0



Finding the minimum value of y = 3-sinx / 1 + cosx


According to the geometric meaning
Y is the slope between the point (- cosx, SiNx) and the point (1,3) on the unit circle
Let the slope of the line passing through point (3,1) be K, Y-3 = K (x-1) kx-y + 3-K = 0
When tangent
The distance from the center of the circle to the straight line is 1
Then | 3-K | / radical (K & sup2; + 1) = 1
k²+1=k²-6k+9
k=4/3
So the minimum is 4 / 3



If the intersection point P (x, y) of the line y = x + 2K + 1 and the line x + 2Y = 4 is in the second quadrant with respect to the y-axis, then the value range of K?


First, find the intersection of two straight lines, x + 2K + 1 = 2-0.5x, and get x = 2 / 3 - (4 / 3) * K
y=5/3+(2/3)*k
Because the point P is symmetric about the Y axis in the second quadrant, then the point P should be in the first quadrant, x = 2 / 3 - (4 / 3) * k > 0, K0, k > - 5 / 2
The range of K is (- 5 / 2,1 / 2)