How to write 45.55 - (6.82 + 15.55) with simple operation (recursive equation)?

How to write 45.55 - (6.82 + 15.55) with simple operation (recursive equation)?

45.55-(6.82+15.55)
=45.55-15.55-6.82
=30-6.82
=23.18

y=3/x ①
3x+4y+b=0 ②
The results are as follows: 1) for simultaneous ① and ②, 3x + 12 / x + B = 0, i.e., 3x & # 178; + BX + 12 = 0, Δ = B & # 178; - 4 × 3 × 12 = 0, i.e., B = ± 12
D = | - 12-3 | / radical 3 & # - 178; + 4 & # - 178; = 3 the minimum distance between the point on the curve y = 3 / X (x > 0) and the straight line 3x + 4Y + 3 = 0 is 3
Q: if B = ± 12, why should b take - 12?

Of course, you can take it!
But look at the title: x > 0
If it's 12, 3x ^ 2 + 12x + 12 = 0
X = - 2, contradiction!
[questions are welcome]

19-99 is equal to?
Below 1.10 above 2.10 3.10

-80

Power series expansion of arctanx ln ((1 + x ^ 2) ^ 1 / 2)

y=arctanx-ln((1+x^2)^1/2)
y'=1/(1+x^2)-x/(1+x^2)
=1-x^2+x^4-x^6+...
-x+x^3-x^5+.
y=x-x^2/2-x^3/3+x^4/4+x^5/5+.

() divided by 16 = 18: () = 32% = 0.75%
emergency

12 divided by 16 = 18:24 = 32, 24 = 75 = 0.75

For quadratic function y = AX2; + BX + C, if x = - 1, does y = 0 have real numbers a, B, C such that x ≤ y ≤ 1 / 2 (x2 + 1) holds for all real numbers x

Y = ax & sup2; + BX + C, where x = - 1, y = 0,
a-b+c=0…… ①
If x ≤ y ≤ 1 / 2 (X & sup2; + 1) holds for all real numbers x, let x = 1: 1 ≤ y ≤ 1 / 2 (1 & sup2; + 1)
1 ≤ y ≤ 1, so y = 1. When x = 1, y = 1
a+b+c=1.…… ②
If y ≥ x is constant for all real numbers x, ax & sup2; + BX + C ≥ x can be obtained
ax²+(b-1)x+c≥0,
So a > 0, △ = (B-1) & sup2; - 4ac ≤ 0 ③
By substituting 1-B = a + C into 3, we get: (a + C) & sup2; - 4ac ≤ 0,
(a-c)²≤0,
So a = C, and a = 1 / 4, B = 1 / 2, C = 1 / 4

What is the quotient of the sum of 2 / 3 and its reciprocal divided by 3 / 5

The quotient is X
3/5x=2/3+3/2
3/5x=4/6+9/6
3/5x=13/6
x=13/6÷3/5
x=65/18

In: A / 3, X-Y / 2, - 1 / 2Y square, - x, monomial has? Polynomial has? Integer has?

The monomials are x / 3, - 1 / 2Y & #, - X
The polynomial is X-Y / 2
They are all integral

What's the weight of a meter of 6 square copper wire?
There is a formula

Volume x specific gravity = weight
6 if the square meter * 1 * 8.9 = 53.4 tons
6 if it is decimeter * 10 * 8.9 = 534kg
6 if cm * 100 * 8.9 = 5340kg

1、 A / x-a + B = 1 (B ≠ 1) 2. M / x-n / x + 1 = 0 (m ≠ n, Mn ≠ 0)