What is the value range of X that makes the formula √ - 2x + 3 meaningful? Please hurry`` Is the root of the root number``

What is the value range of X that makes the formula √ - 2x + 3 meaningful? Please hurry`` Is the root of the root number``

-2X + 3 > = 0 so x

If - 2x ^ 2a-1 + 5 = 0 is a linear equation with one variable, then 2a-1=

If - 2x ^ (2a-1) + 5 = 0 is a linear equation with one variable
Then 2a-1 = 0

If x ^ 4-5x ^ 3 + 8x ^ 2-5x + 1 = 0, then 1 / x + X=

x^4-5x^3+8x^2-5x+1=0
x^2(x^2-5x+8-5/x+1/x^2)=0
x^2[(x^2+1/x^2)-5(x+1/x)+8]=0
x^2[(x+1/x)^2-5(x+1/x)+6]=0
x^2(x+1/x-6)(x+1/x+1)=0
If x = 0, then the original formula does not hold
So x ≠ 0, x ^ 2 ≠ 0
∴(x+1/x-6)(x+1/x+1)=0
Ψ x + 1 / x = 6 or - 1
Please take the answer and support me

Simplify and evaluate a + 1 + √ (A & # 178; + 2A + 1) / A & # 178; + A + (1 / a) where a = - 1 - √ 5
a+1+√（a²+2a+1）/a²+a +1/a
Only those in brackets are under the root

a=-1-√5

Merge similar items: 5a-3x + 4A + 8x-5ax-2x

The original formula is 5A + 4A - (3x + 2x) + 8x-5ax
＝9a＋8x－5x－5ax
＝9a＋3x－5ax

N-order matrix A is not only an orthogonal matrix but also a positive definite matrix. It is proved that a is an identity matrix

You only said that matrix A is a diagonal matrix, and it may be a multiple of the identity matrix. You can't say that a is the identity matrix. To explain the identity matrix, in addition to stating: "the orthogonal matrix indicates that a ^ (- 1) = a ', the positive definite matrix indicates that a contracts with E, that is, a = c'ec, so a ^ (- 1) = a' = (c'ec) '= c'ec = a, so a is a diagonal matrix", and adding: "because a is an orthogonal matrix, so a ^ (- 1) = 1, So a is the identity matrix "!

A1 = 0, the limit of an is 2, a (n + 1) = (2 + an) ^ 0.5 prove that the series (2-An) ^ 0.5 converges

It is easy to prove that the series is a positive series. The limit form of the ratio discriminant is LIM (n →∞) √ (2-An + 1) / √ (2-An) = LIM (n →∞) √ [(2 - √ (2 + an)) / (2-An)]. ∵ n →∞, an → 2. If t = √ (2 + an), then an → 2 is equivalent to t → 2

Do not change the value of fraction 0.3x-0.5x + 1, change it into an integer, and the result is?

3x-5x / 20 + 10
Landlord, please accept!

If the function f (x) defined on [- 20012001] satisfies, for any x1, X2 ∈ [- 20102010], there is f (x1 + x2) = f (x1) + F (x2) - 2009,
And when x > 0, if f (x) > 2009, then the sum of the maximum and minimum of F (x) is?

Let g (x) = f (x) - 2009, then it is known that for any x1, X2 ∈ [- 20102010], there is g (x1 + x2) = g (x1) + G (x2),
When x > 0, G (x) > 0
Let X1 = x2 = 0, then G (0) = 0,
Let x 1 = x, x 2 = - x, then G (- x) = - G (x), so g (x) is an odd function
If the maximum value of G (x) is m, then the minimum value is - M
Therefore, from F (x) = g (x) + 2009, the maximum value of F (x) is m + 2009, and the minimum value is - M + 2009,
So the sum = 2009 * 2 = 4018

It is known that X of y = K + 1 is an inverse proportional function, and when x = - 2K, y = K + 1. Find the analytic expression of the function of Y and X. when x = 2 and 1 of 2, find the value of Y
When y = - 4, find the value of X

A:
Y = (K + 1) / X is an inverse proportional function
When x = - 2K: y = (K + 1) / (- 2K) = K + 1
So: - 2K = 1, k = - 1 / 2
So: y = 1 / (2x)
When x = 2 and 1 / 2 = 5 / 2: y = 1 / (2 * 5 / 2) = 1 / 5
When y = - 4, y = 1 / (2x) = - 4, x = - 1 / 8