If the monomials 2mx ^ ay and - 5nx ^ (2a-3) y are monomials of X and y, and their sum is monomials (1) Find the value of (7a-22) ^ 2003 (2) If 2mx ^ ay-5nx ^ (2a-3), y = 0 and XY ≠ 0, find the value of (2m-5n) ^ 2003

If the monomials 2mx ^ ay and - 5nx ^ (2a-3) y are monomials of X and y, and their sum is monomials (1) Find the value of (7a-22) ^ 2003 (2) If 2mx ^ ay-5nx ^ (2a-3), y = 0 and XY ≠ 0, find the value of (2m-5n) ^ 2003

A = 2a-3, then a = 3
(1) (7a-22)^2003=(21-22)^2003
=(-1)^2003
=-1
(2) 2mx^ay-5nx^(2a-3)y=2mx³y-5nx³y=(2m-5n)x³y=0
So 2m-5n = 0
So (2m-5n) ^ 2003 = 0 ^ 2003 = 1

If the monomials 2mx ^ ay and - 5nx ^ 2a-3y are monomials of X, y, and their sums are monomials
Find the value of (7a-22) ^ 2003. If 2mx ^ ay-5nx ^ 2a-3y is equal to 0 and XY is not equal to 0, find the value of (2m-5n) ^ 2003. Explain that 2mx ^ ay, a is the power of 2mx, y is not. - 5nx ^ 2a-3y, 2a-3 is the power of - 5nx, y is not,

Because sum is monomial
So they are of the same kind
So a = 2a-3
A = 3
Question 1: the original formula = 1
Question 2: equal to 0 means 2m-5n = 0
After you meet the number of 2003 power, you can rest assured on the line, either 1 or - 1

If "*" is a new algorithm, let a * b = a2-a × B, and try to solve the equation (- 2) * x = 312

∵ a * b = a2-a · B, ∵ (- 2) * x = 312. ∵ 4 - (- 2) x = 312, 2x = - 12, the solution is: x = - 14

Simple operation. (2030-18 × 35 △ 35)

（2030-18×35)÷35
=2030÷35-18×35÷35
=58-18
=40

Calculation: (A / A-B-A & # 178; - 2Ab + B & # 178;) / (A / A + B-A & # 178; / A & # 178; - B & # 178;) + 1

The original formula = (A & # 178; - AB-A & # 178;) / (a-b) &# 178; △ A & # 178; - AB-A & # 178;) / (a + b) (a-b) + 1
=-ab/(a-b)²×[-(a+b)(a-b)/ab]+1
=(a+b)/(a-b)+1
=(a+b+a-b)/(a-b)
=2a/(a-b)

Fill - 4. - 3. - 2. - 1.0.1.2.3.4 into nine lattices. Add each row, column and diagonal to get zero

3 -4 1
-2 0 2
-1 4 -3

2 / 5x-1 / 3Y + 1 = 0 2x + 2Y = 6 how to solve this system of equations

2 / 5x-1 / 3Y + 1 = 0 multiply by 15
6x-5y+15=0
6x=5y-15
2x+2y=6
6x+6y=18
6x=18-6y
therefore
5y-15=18-6y
5y+6y=18+15
11y=33
y=3
x=0

How to do the first question on the third page of the supplementary exercises of mathematics in the fifth grade

Right
（1）x+36=64 (2) x-0.8=1.9
x=64-36 x=1.9+0.8
x=28 x=2.7

It is proved that no matter what the value of X is, the value of the algebraic formula 2x2-4x + 3 is always greater than 0

It is proved that the value of 2x2-4x + 3 = 2 (x2-2x + 1) + 1 = 2 (x-1) 2 + 1, ∵ (x-1) 2 ≥ 0, ∵ 2x2-4x + 3 is always greater than 0

Given 5A = 4b, find a + B divided by B

a/b=4/5
（a+b）÷b=4/5+1=1.8