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*It is a new algorithm: a * b = A & sup2; + 2Ab, for example, 3 * (- 2) = 3 & sup2; + 2x3x (- 2)= Find the value of 2 * (- 3), the solution of 2 * x = 2 equation (- 2) * (1 * x) = x + 9 equation For example, 3 * (- 2) = 3 & # 178; + 2x3x (- 2) = (- 3)
2*（-3）=2²+2x2x(-3)=4-12=-8
2 * x = 2 deduce 2 & # 178; + 2x2xx = 2 simplify 4x = - 2 x = - 1 / 2
(- 2) * (1 * x) = x + 9 deduce (- 2) & # 178; + 2x (- 2) x (1 & # 178; + 2x1xx) = x + 9 simplify 9x = - 9 x = - 1
*It is a new algorithm: a * b = A & # 178; + 2Ab, find 2 * (- 1); if 2 * x = 2, find X; if (- 2) * x = - 2 + X, find X
2*（-1）=2^2+2*2*(-1)=4-4=0
2 * x = 2 ^ 2 + 2 * 2 * x = 4 + 4x = 2, the solution is x = - 1 / 2
(- 2) * x = (- 2) ^ 2 + 2 * (- 2) * x = 4-4x = - 2 + X, x = 6 / 5
The algorithm for defining the operation "@" is :x@y=x Square - y, then（ 2@3 )@4=( )
( 2@3 )@4=(4-3)@ 4=1@4=1-4=-3
The root of the equation 3x + a = x + 7 of X is a positive number, and the value range of the real number a is obtained
3x+a=x+7
2x=7-a
x=3.5-a/2
Because the root is a positive number
Therefore, x = 3.5-a / 2 > 0
a
It is known that the vertex of parabola C is at the origin, the focus is f (0,1), and it passes through point a (2, t), (I) to find the value of T; (II) if points P and Q are two moving points on parabola C, and the slopes of straight line AP and AQ are opposite to each other, whether the slope of straight line PQ is a fixed value, if not, find this value; if not, please explain the reason
(1) According to the condition: the parabola passes through the origin, and the focus is on the y-axis, let the parabola equation be x2 = 2PY & nbsp; from the condition that the focus is f (0,1), the parabola equation is x2 = 4Y & nbsp; & nbsp; & nbsp (3 points) ｜ substituting point a into x2 = 4Y, t = 1 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp (6 points) (II) when KAP and KAQ do not exist, one point of P or Q coincides with a, one point is parallel to the x-axis of a, one of which has a slope of 0 and one is infinite, which is not in accordance with the meaning of the problem. Let the slope of AP be K, and the slope of AQ be - K, then the equation of AP is Y-1 = K (X-2), that is, y = KX - (2k-1) simultaneous equation: y = KX − (2k − 1) x2 = 4Y, eliminating y, then: x2-4kx + 4 (2k-1) = 0 & nbsp ; … (9 points) ∵ xaxp = 4 (2k-1), a (2,1) ∵ XP = 4k-2 ∵ YP = 4k2-4k + 1. Similarly, XQ = - 4k-2, YQ = 4k2 + 4K + 1 KPQ = & nbsp; YQ − ypxq − XP = − 1 is a fixed value independent of K (15 points)
2008 * 2009 / 2008
2008×2008/2009
=（2009-1）×2008/2009
=2009×2008/2009-1×2008/2009
=2008-2008/2009
=January 2007 / 2009
In the cube abcd-a'b'c'd ', e and F are the midpoint of edges AD and ab
Even DB because e, f are. Midpoint
So EF is parallel to DB
The cube abcd-a'b'c'd'dd'is parallel to b'b
The angles DBB 'and BB'd' are 90 degrees
So BD is parallel to d'b '
Because d'b 'is in the plane cb'd'
So EF is parallel to the plane cb'd '
The cubic power of 7x-6x is the cubic power of y = 3x, the cubic power of y = 3x is the cubic power of 6x, the square of y-3x is the cubic power of y-10x
I can't understand your topic at all. If you use a ^ power table, for example, the cubic power of X is x ^ 3, so the formula may be understood. Pay attention to adding brackets, or you won't be able to see it clearly
Let a ^ 2 + 2A = B ^ 4-2b ^ 2 = 1, and 1-ab ^ 2 not equal to 0, prove ((AB ^ 2 + B ^ 2 + 1) / a) ^ 2007 = 1
Figure guessing idioms 1 2 3 4 5 6 0 9 () 1 2 5 6 7 8 9 () 1 + 2 + 3 () 333 555 () 3 5 () 5 10 ()
9 inches + 1 inch = 1 foot
Urgent homework tonight!
1 2 3 4 5 6 0 9 (scattered) 1 2 5 6 7 8 9 (lost three or four) 1 + 2 + 3 (in succession) 333 555 (three or five groups) 3 5 (not three or four) 5 10 (one or five 10) 9 inches + 1 inch = 1 foot
RELATED INFORMATIONS
- 1. a. B is a rational number. Now a new algorithm is provided: a △ B = the square of a + 2Ab, if (- 2) △ x = - 6 + X, then X=
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- 5. In the original algorithm of rational number, we define a new operation "(+)" as follows: When a > or = B, a (+) B = B × B
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- 12. A new algorithm is provided: a ∧ B = A & # 178; + 2Ab if 2 ∧ (- x) = - 2 + X, calculate the value of X
- 13. If the monomials 2mx ^ ay and - 5nx ^ (2a-3) y are monomials of X and y, and their sum is monomials (1) Find the value of (7a-22) ^ 2003 (2) If 2mx ^ ay-5nx ^ (2a-3), y = 0 and XY ≠ 0, find the value of (2m-5n) ^ 2003
- 14. What is minus three squared
- 15. If the 5A power of 2 is equal to the 3B power of 5 and the 2C power of 10, find the relationship between a, B and C
- 16. It is expressed in the form of power: [(X-Y) square · (Y-X) third power
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